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Angular Momentum - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Angular Momentum is considered one of the most asked concept.

  • 39 Questions around this concept.

Solve by difficulty

A particle of mass m moves along line PC with velocity ν as shown. What is the angular momentum of the particle about P?

A particle of mass 2 kg is on a smooth horizontal table and moves in a circular path of radius 0.6 m. The height of the table from the ground is 0.8 m. If the angular speed of the particle is 12 rad s-1, the magnitude (in kg m2s-1) of its angular momentum about a point on the ground right under the centre of the circle is :

Angular momentum of a single particle moving with constant speed along circular path :
 

The position vector of 1 kg object is r=(3i^j^)m and its velocity v=(3j^+k^)ms1. The magnitude of its angular momentum is xNm where X is:

A small particle of mass m is projected at an angle Θ with the x-axis with an initial velocity v0 in the x-y plane as shown in the figure. At a time

t<v0sinΘg

the angular momentum of the particle is

where i^,j^ and k^ are unit vectors along x,y and z -axis respectively.

When a dancer folds her arms she spins faster on ice. This is due to 

A solid homogeneous sphere is moving on a rough horizontal surface, partly rolling and partly sliding. During this kind of motion of this sphere:

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The term moment of momentum is called

If L and P represent the angular momentum and linear momentum respectively of a particle of mass ' m ' having position vector r=a(i^cosωt+j^sinωt). The direction of force is
 

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Concepts Covered - 1

Angular Momentum
  • The moment of linear momentum of a body with respect to any axis of rotation is known as angular momentum. If  P is the linear momentum of a particle and its position vector from the point of rotation is r then angular momentum is given by the vector product of  linear momentum and position vector. 

                                         

L=r×PL=r×P=r×(mV)=m(r×V)|L|=rpsinθ, where θ is the angle between r and p.|L|=mvrsinθ

- Its direction is always perpendicular to the plane containing vector r and P and with the help of right hand screw rule we can find it.

Its direction will be perpendicular to the plane of rotation and along the axis of rotation
- Lmax =rP( when θ=90)
- Lmin =0( when θ=00)
- SI Unit- Joule-sec or kgm2/s
- Dimension- ML2T1
- In case of circular motion

As rv and v=ωr and I=mr2

L=mvr=mr2ω=Iω


So in vector form L=Iω
- The net angular momentum of a system consists of n particles is equal to the vector sum of angular momentum of each particle.

Lnet=L1+L2+Ln
 

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Angular Momentum

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