Careers360 Logo
JEE Main 2024 Cutoff for IIIT Nagpur - Opening and Closing Ranks

Angular Momentum - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Angular Momentum is considered one of the most asked concept.

  • 15 Questions around this concept.

Solve by difficulty

A particle of  mass m moves  along line  PC  with velocity \nu  as shown. What  is the angular momentum of the particle about  P?

A small particle of mass m is projected at an angle \Theta with the  x-axis with an initial velocity \upsilon _{0} in the  x-y plane as shown in the figure. At a time t< \frac{\upsilon _{0}\sin \Theta }{g}, the angular momentum of the particle is

where \hat{i},\hat{j}\, and\, \hat{k} are unit vectors along x,y and z-axis respectively.

Concepts Covered - 1

Angular Momentum
  • The moment of linear momentum of a body with respect to any axis of rotation is known as angular momentum. If  P is the linear momentum of a particle and its position vector from the point of rotation is r then angular momentum is given by the vector product of  linear momentum and position vector. 

                                         

\vec{L} =\vec{r}\times\vec{P}        

\vec{L} =\vec{r}\times\vec{P} = \vec{r}\times(m\vec{V}) = m(\vec{r}\times\vec{V})

        \left | \vec{L} \right | = rpsin\theta,  where \theta is the angle between r and p.

        |\vec{L}|=mvrsin\theta

  • Its direction is always perpendicular to the plane containing vector  r and P and with the help of right hand screw rule we can find it.

 Its direction will be  perpendicular to the plane of rotation and along the axis of rotation

 

 

  • L _{max}=r*P \ (when \ \theta =90^0)

  • L _{min}=0 \ (when \ \theta =0^0)

  • SI Unit- Joule-sec or  kg-m^2/s

  • Dimension- ML^2T^{-1}

  •  In case of circular motion

As \vec{r}\perp \vec{v} and v = \omega r and I = mr^2

L=mvr=mr^2\omega =I\omega

So in vector form \vec{L}=I\vec{\omega }

  • The net  angular momentum of a system consists of n particles is equal to the vector sum of angular momentum of each particle.

\vec{L}_{net}=\vec{L}_1+\vec{L}_2.......+\vec{L}_n

Study it with Videos

Angular Momentum

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Get Answer to all your questions

Back to top