With an 80 percentile and a rank around 1,00,000, your chances of getting CSE or ECE in BVRIT (Bharatiya Vidya Bhavan’s Rajiv Gandhi Institute of Technology, Narsapur) depend on the category, gender, and home state quota.

BVRIT is a popular institute in Telangana under the TS EAMCET and JEE Mains

I think you want to say 86 percentile because JEE Mains releases merit lists based on percentile, not percentages. So, with this percentile, you can get into several government colleges or private colleges in the city of Hyderabad. There many colleges in  hyderabad that accept  mains score, some popular ones

Hello,

There is good news for you. You can get admission to the JECRC Foundation for the B.Tech program with just 12th marks. They can give you admission without a JEE Mains score; they just need your 12th marks, and based on this merit, you can obtain a seat in

Hello

With 88 percentile in JEE Main 2025 , your approximate All India Rank would be between 1,06,000 and 1,20,000 (for the general category).

CSE (Computer Science Engineering):

Not possible in top NITs or IIITs .

Unlikely in lower NITs unless you belong to a reserved category or have home

Hello aspirant,

The syllabus of JEE MAINS PAPER 2A for degree B.Arch inculdes three subjects: maths, aptitude test, and drawing.

The exam is of 400 marks with 77 questions and of 3 hours. -1 negative marking will be given for every wrong answer of maths or numerical value question. For

That's great! MA in English Literature is a wonderful choice if you love reading and writing. It opens up many career options like teaching, writing, editing, and more. Best wishes for your journey!

Hello

NIT Kurukshetra – Civil Engineering (JEE Main Cut-offs)

2024 Round 3 and 4 Final Closing Ranks

All India (AI Other State) Category – Gender Neutral

Opening Rank: Approximately 15,535

Closing Rank: Around 29,292 in Round 1, and up to 33,266 by Round 4

Home State (HS Haryana) Category –

Hello Srinidhi,

In order to acquire Mechanical Engineering at NIT Kurukshetra, generally the required JEE Main rank will be in the range of:

• Home State Quota (Haryana): Up to 40,000 (general category)
• Other State Quota: Up to 20,000-25,000 (general category)

The cutoffs that I have provided above change from year

Hello aspirant,

As per your query, the JEE rank required for NIT Kurukshetra in Computer Science Engineering branch is,

All India Closing Rank (General category) : 6562

Home state Closing Rank (General category) : 8198

For more information, click on the link given below,

https://www.careers360.com/university/national-institute-of-technology-kurukshetra/cut-off

Regards

According to the eligibility criteria for JEE Advanced, the candidates must have appeared in Class 12th and scored 75% aggregate marks. For the first time, you appeared in the CBSE Class 12 board exam in 2024, and in 2025, you appeared in the 12th examination from the NIOS board and