24 Questions around this concept.
A resistance of $40 \Omega$ is connected to a source of alternating current rated $220 \mathrm{~V}, 50 \mathrm{~Hz}$. Find the time taken by the current to change from its maximum value to the rms value:
What will be the power factor of an Ac circuit having resistance (R) and inductance (L) connected in series and angular velocity $\omega:$?
Which of the following is true about pure resistive circuit-
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A 220 V A.C. supply is connected between points A and B. What will be the potential difference V across the resistor?

Physical quantity whose magnitude changes continuously with the time between zero and maximum value whose direction reverses periodically is called :
AC voltage applied to a resistor:
When a constant voltage source or battery is applied across a resistor current is developed in resister. This current has a unique direction and flows from the negative terminal of a battery to positive terminal. The magnitude of the current remains constant as well. If Direction of current through resistor changes periodically then current is called alternating current.

Voltage V(t) is applied across resistance R. V(t) is sinusoidal voltage with peak Vm and time period T.
$
T=\frac{1}{f}=\frac{2 \pi}{\omega}
$
Where $f$ is frequency and $\omega$ is angular frequency. This kind of circuit is a purely resistive circuit. According to Kirchhoff's law -
$
\begin{aligned}
v(t) & =R i(t) \\
i(t) & =\frac{v(t)}{R} \\
i(t) & =\frac{V_m \sin (\omega t)}{R} \\
i_m & =\frac{V_m}{R} \\
i(t) & =i_m \sin (\omega t)
\end{aligned}
$
Here voltage and current has same frequency and both are in same phase. Therefore phase difference between current and voltage is 0 .
The maximum value of voltage is achievd at $\mathrm{t}=\mathrm{T} / 4$.
Peak current, $i_0=\frac{V_0}{R}$.
Power factor:
Ratio of resistance and impedance. The power factor also denoted by $\cos \phi$.
power factor $=\cos (\phi)=1$
Power:
$
P=V_{r m s} i_{r m s}=\frac{V_0 i_0}{2}
$
Time difference
$
\text { T.D. }=0
$
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