UPES B.Tech Admissions 2025
ApplyRanked #42 among Engineering colleges in India by NIRF | Highest CTC 50 LPA , 100% Placements
AC voltage applied to a capacitor is considered one of the most asked concept.
19 Questions around this concept.
In an a.c. circuit the voltage applied is The resulting current in the circuit is . The power consumption in the circuit is given by
AC voltage applied to a capacitor:
The circuit containing alternating voltage source V=V0sinωt connected to a capacitor of capacitance C.
Suppose at any time t, q be the charge on the capacitor and i be the current in the circuit. Since there is no resistance in the circuit, so the instantaneous potential drop across the capacitor must be equal to applied alternating voltage so,
Since is the instantaneous current in the circuit so,
Where, is the peak value of current.
Comparing equation of current with V=V0sinωt ,we see that in a perfect capacitor current leads the emf by a phase angle of π/2.
Again comparing peak value of current with ohm's law ,we find that quantity 1/ωC has the dimension of the resistance.
Thus the quantity is known as capacitive reactance.
Phase difference (between voltage and current):
Power :
P= 0
Power factor :
Time difference:
T.D =
"Stay in the loop. Receive exam news, study resources, and expert advice!"