The exact cutoff percentile is not yet announced by National Testing Agency to be eligible for JEE Advance and since the exam was conducted in various shifts this year it cannot be estimated. 

I suggest you to wait for the officials to announce the precise percentile.

If you have any

hello kishan pandey,

yes,jee advanced is enough to earn UG (b.tech) admission in IISC, bangalore.to know more,please refer the following link:

• https://www.careers360.com/university/indian-institute-of-science-bangalore

all the best!

note:if any links available,copy and paste it in the url bar of your browser.

I Hope this information will be useful to you.

if you

Hello. You have a good percentile. It means that 6% of tot students appeared in the exam are ahead of you. (Approx Tot. Students appeared- 874469).

Though it is difficult to predict the cutoff for any particular college now but any rank below 2,00,000 might get you qualified for JEE

Yes they should follow the jee advanced syllabus.

But there are some topics which are included in only jee mains .

And there are some topics which included in onle jee advanced.and sometimes they give one or two questions from the concept beyond syllabus.

So it is sufficient to follow

Hello,

I would suggest you to visit the career360's link given below which contains all the information needed by you ias well as solved paper from last 15-18 years which will help you analyse as well as build up your knowledge.

The link for the same is:https://engineering.careers360.com/articles/jee-advanced-question-papers

If you face

Visit : https://engineering.careers360.com/result-predictor

hii sah

frankly to say you have very low percentile , while its hard to decide by the percentile as the admission goes by RANK not by percentile since find out your RANK fallow the below way

To calculate you rank you can use the formulae given below - 

Rank=(total

Hello Navyasri..

Percentile= (marks you got*100)/(toppers marks in that session).

According to careers360 rank formula, 

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 1,05,933.

As per previous year jee mains, any rank below

Hello Kanhaiya kumar..

According to careers360 rank formula, 

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 2,49,661.

As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.

Hello Harshavardhan..we can't predict marks as it is percentile, but we can predict the rank.

According to careers360 rank formula, 

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 3,98,273.

As per previous year