hello rahul goswami ,

Computer Science and Engineering :-

opening rank : - 38

Closing rank : - 65

this details are from tear 2018 ranks changes every year .

Hii

This is the first time when IIT-H has added AI branch. There are no records of closing and opening ranks for that course. So it is difficult to predict that. Closing rank depends upon popularity of course and college. So I think this is the first time for AI.

hello Santosh,

you can predict your rank here by feeling details.

click the link and predict

https://engineering.careers360.com/jee-advanced-rank-predictor

thank you.

Dear Shivam, to be eligible for JEE Advanced, you need to qualify for JEE Mains candidates should begin the top 2,24,000 candidates including all the categories. The percentage of each Category is OBC-NCL 27%, SC-15%, ST- 7.5% and Open Category is 50.5%. And regarding the educational qualification, you need to

As per the official, The candidates applying for JEE Advanced 2019 should have appeared in Class 12 in 2018 or 2019 for the first time. You can check the complete information about the exam with the given below link.

https://engineering.careers360.com/articles/jee-advanced-eligibility-criteria

Good Luck!

I would suggest you to go through with the given below link to download JEE Advance Sample Papers.

https://engineering.careers360.com/articles/jee-advanced-question-papers

Good Luck!

Hello,

A candidate gets a maximum of two attempts in consecutive years to appear for JEE Advanced.

I would suggest you to visit the career360's link given below for more details on the ligibility criteria.

The link for the same is:https://engineering.careers360.com/articles/jee-advanced-eligibility-criteria

Hope this helps and all the very best!

hello aspirant......

the difference between jee mains paper 1 and paper 2 is the jee mains paper 1 is for the candidates those are interested in the stream of engineering and the jee mains paper 2 is for going in the stream of architecture and in the jee mains paper