EASYParul University B.Tech Admissions 2025
Registrations Deadline- 12th June | India's youngest NAAC A++ accredited University | NIRF rank band 151-200 | 2200 Recruiters | 45.98 Lakhs Highest Package
Voltmeter - Practice Questions & MCQ
Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main
Quick Facts
-
Voltmeter is considered one of the most asked concept.
-
54 Questions around this concept.
Solve by difficulty
The AC voltage across a resistance can be measured using a :
To verify Ohm’s law, a student connects the voltmeter across the battery as shown in the figure. The measured voltage is plotted as a function of the current and the following graph is obtained. If Vo is almost zero, then identify the correct statement.
The reading in the ideal voltmeter (V) shown in the given circuit diagram is:
A cell of emf $
90 \mathrm{~V}
$ is connected across series combination of two resistors each of $
100 \Omega
$ resistance. A voltmeter of resistance $
400 \Omega
$ is used to measure the potential difference across each resistor. The reading of the voltmeter will be:
The net resistance of a voltmeter should be large to ensure that
In the circuit shown, below a student performing Ohm's law experiment accidentally puts the voltmeter and ammeter as shown in the circuit below, the reading in the voltmeter will be close to:
In a 20 m deep lake, the bottom is at 4°C. The air temperature is constant –10°C. The thermal conductivity of ice is 4 times that of water. Neglecting expansion of water at freezing. The maximum thickness of the ice will be:
Concepts Covered - 1
Voltmeter
Voltmeter
It is a device used to measure Potential difference and is always put in parallel with the circuit element whose voltage is to be measured
Convert the galvanometer into a voltmeter by connecting a large series of resistances.
- The equivalent resistance of the combination is $G+R$
- The required value of high resistance to be connected in series with the galvanometer is
$$
R=\frac{V}{I_g}-G=\left[\frac{V}{V_g}-1\right] G
$$
V is the total voltage applied across the circuit and $V_g$ is the total voltage drop across the galvanometer.
- If $n^{\text {th }}$ part of the applied voltage across galvanometer, that is $V_g=V / n$, then $R=(n-1) G$.
Study it with Videos
Voltmeter"Stay in the loop. Receive exam news, study resources, and expert advice!"
Get Answer to all your questions
JEE Main Articles
Back to top