VIT - VITEEE 2025
National level exam conducted by VIT University, Vellore | Ranked #11 by NIRF for Engg. | NAAC A++ Accredited | Last Date to Apply: 7th April | NO Further Extensions!
8 Questions around this concept.
Average radius of toroid made on ring of non-magnetic material is
A toroidal solenoid has 3000 turns and a mean radius of 10 cm. It has a soft iron core of relative permeability 2000. What is the magnitude of the magnetic field in the core when a current of 1 A is passed through the solenoid?
A loosely wound helix made of stiff wire is mounted vertically with the lower end just touching a dish of mercury. When a current from the battery is started in the coil through the mercury :
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A toroid of mean radius ' a ', cross-section radius ' r ' and a total number of turns N. it carries a current ' i '. The torque experienced by the toroid if a uniform magnetic field of strength B is applied.
A toroid having 1000 turns per meter and carrying a current 5 A the value of the magnetic field at point inside is
For a toroid having n turns per unit length and carrying current i, the value of the magnetic field at the point inside the toroid is
Direction: In the following question, a statement of Assertion (A) is followed by a statement of reason (R). Mark the correct choice as:
Assertion: For a toroid, the magnetic moment is zero.
Reason: The magnetic field outside the volume of the current current-carrying toroid is zero.
National level exam conducted by VIT University, Vellore | Ranked #11 by NIRF for Engg. | NAAC A++ Accredited | Last Date to Apply: 7th April | NO Further Extensions!
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A toroid of n turns, mean radius R and cross-sectional radius a carry current I. It is placed on a horizontal table taken as an x-y plane. Its magnetic moment m.
Toroid -
If we try to bend a solenoid in the form of a ring then the obtained shape is a Toroid. So, a toroid can be considered a ring-shaped closed solenoid. Hence it is like an endless cylindrical solenoid. From the given figure we can understand Toroid much better.
Now to obtain the magnetic field by a toroid, let us consider a toroid having N turns.
Here, we will now apply Ampere circuital law to calculate the magnetic field of a toroid. Suppose we have to find the magnetic field B at a point P inside the toroid as shown below in figure -
Let us take an amperian loop which is a circle through point P and concentric inside the toroid. By symmetry, field will have equal magnitude at all points of this circle and this field is tangential to every point in the circle
Thus,
From the above result, B varies with r i.e. field B is not uniform over the cross-section of the core because as we increase 'r' the B varies.
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