Search Colleges, Exams, Schools & more
Login
The Intermediate Value Theorem - Practice Questions & MCQ
Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main
Quick Facts
-
5 Questions around this concept.
Solve by difficulty
EASYIf $f(x)=x^2-1$, then $f(x)=\frac{5}{4}$ has atleast ___ Solution in $[-1,2]$
Concepts Covered - 1
The Intermediate Value Theorem
The Intermediate Value Theorem (IMVT)
Let $f$ be continuous over a closed interval $[a, b]$ and $f(a) \neq f(b)$. If $z$ is any real number between $f(a)$ and $f(b)$, then there is at least one $x$ in $[a, b]$ satisfying $f(x)=z$
An important result from IMVT
If $f(x)$ is a continuous function in $[a, b]$ and $f(a)$ and $f(b)$ are of opposite signs, then there is at least one root of $f(x)$ lying in $(a, b)$.
Study it with Videos
"Stay in the loop. Receive exam news, study resources, and expert advice!"
Books
Reference Books
Clear your Basics with NCERT
E-books & Sample Papers
Get Answer to all your questions
B.Tech/B.Arch Admissions OPEN
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
UPES B.Tech Admissions 2026
ApplyLast Date to Apply Extended till Today, 30th April | Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
Amrita University B.Tech 2026
ApplyRecognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
MAHE, Manipal - B.Tech Admissions 2026
ApplyExtended Application Deadline: 30th April | NAAC A++ Accredited | NIRF Rank #3
Reva University B.Tech Admissions 2026
ApplyQS I-Gauge Diamond Rated | NAAC A+ Accredited | 621 Recruitment Partners | INR 40 LPA Highest CTC | 4482 Job offers
Manav Rachna-B.Tech Admissions 2026
ApplyNAAC A++ Grade | Recognized as Category-1 Deemed to be University by UGC | 41,000 + Alumni Imprints Globally