Sum of an infinite AGP is considered one the most difficult concept.
11 Questions around this concept.
Find the value of $\left(\frac{1}{1!}+\frac{1}{3!}+\frac{1}{5!}+\ldots \infty\right)$
Find the value of $\left(\frac{1}{3!}+\frac{1}{4!}+\frac{1}{5!}+\ldots \ldots \ldots \infty\right)$
The sum of an infinite AGP
$S_{\infty}$ denotes the sum of an infinite AGP. This sum is a finite quantity if $-1<r<1$
$
\mathrm{S}_{\infty}=a+(a+d) r+(a+2 d) r^2+(a+3 d) r^3 \ldots \ldots
$
Multiply both sides of eq (i) by 'r'
$
r \mathrm{~S}_{\infty}=a r+(a+d) r^2+(a+2 d) r^3+(a+3 d) r^4 \ldots \ldots
$
Subtract eq (ii) from eq (i)
$
\begin{aligned}
& (1-r) \mathrm{S}_{\infty}=a+\left(d r+d r^2+d r^3+\ldots . \text { upto } \infty\right) \\
& \Rightarrow(1-r) \mathrm{S}_{\infty}=a+\frac{d r}{1-r} \\
& \Rightarrow \mathbf{S}_{\infty}=\frac{\mathbf{a}}{\mathbf{1 - r}}+\frac{\mathbf{d r}}{(\mathbf{1}-\mathbf{r})^2}
\end{aligned}
$
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Mathematics for Joint Entrance Examination JEE (Advanced) : Algebra
Page No. : 5.22
Line : 51
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