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    JEE Main 2026 Exam Analysis For Session 2 – Shift Wise Difficulty Level, Paper Review

    Stoichiometric Calculations - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Stoichiometry, Stoichiometric Calculations And Limiting Reagent is considered one of the most asked concept.

    • 31 Questions around this concept.

    Solve by difficulty

     Consider the reaction \mathrm{4 \mathrm{HNO}_{3}(\mathrm{l})+3 \mathrm{KCl}(\mathrm{s}) \rightarrow \mathrm{Cl}_{2}(\mathrm{~g})+\mathrm{NOCl}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})+3 \mathrm{KNO}_{3}(\mathrm{~s})} The amount of  \mathrm{\mathrm{HNO}_{3} }  required to produce \mathrm{110.0 \mathrm{~g} }  of  \mathrm{\mathrm{KNO}_{3} }  is \mathrm{\text { (Given: Atomic masses of } \mathrm{H}, \mathrm{O}, \mathrm{N} \text { and } \mathrm{K} \text { are } 1,16,14 \text { and } 39 \text {, respectively.) } }

    The electrophile, $E^{\oplus}$ attacks the benzene ring to generate the intermediate $\sigma$ - complex. Of the following, which $\sigma$-complex is of lowest energy?

     

    When a hydrocarbon A undergoes complete combustion it requires 11 equivalents of oxygen and produces 4 equivalents of water. What is the molecular formula of A ?

     

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    Given the reaction 

    $2 \mathrm{~N}_2+3 \mathrm{H}_2 \rightleftharpoons 2 \mathrm{NH}_3$

    How many grams of $\mathrm{NH}_3$ will be produced when 56 g of $\mathrm{N}_2$ burnt?

    Identify the limiting Reagent in the following reactions 

    $\mathrm{CH}_4(\mathrm{~g})+2 \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O}(\mathrm{g})$

    Concepts Covered - 1

    Stoichiometry, Stoichiometric Calculations And Limiting Reagent

    Stoichiometry:

    Stoichiometry deals with the calculation of masses (sometimes volumes also) of the reactants and the products involved in a chemical reaction. Before understanding how to calculate the amounts of reactants required or the products produced in a chemical reaction, let us study what information is available from the balanced chemical equation of a given reaction.

    Stoichiometric Calculations:

    Step 1 Write down the correct formulas of reactants and products.

    Step 2 Balance the number of atoms on both reactant and product sides.

    Step 3 Make the equation balanced.

    The coefficients of atoms or molecules are stoichiometric coefficients.

    Limiting Reagent:

    The reactant is consumed first in the reaction. When we are dealing with the balanced chemical equation, if the number of moles of reactants is not in the ratio of the stoichiometric coefficient of the balanced chemical equation, then there should be one reactant that should be limiting reactant.

    % yield

    Sometimes, experimentally, the reaction does not undergo 100% completion because of many factors which are involved in the actual industrial processes. So in such cases, we need the concept of % yield.

    It is defined as the ratio of actual moles of product(s) formed to the number of moles that should have been theoretically formed assuming 100% completion of the reaction.

    \mathrm{\% \:yield = \frac{\:Actual \:number \:of \:moles \:formed}{\:Theoretical \:moles \:that \:should \:have \:formed}}

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    Stoichiometry, Stoichiometric Calculations And Limiting Reagent

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