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    Relation Between Set Notation and Truth Table - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Relation Between Set Notation and Truth Table is considered one of the most asked concept.

    • 24 Questions around this concept.

    Solve by difficulty

    What is negation of x > 5 ?

    If p and q are both false , then which of the following is false ? 

    If $p \rightarrow(p \wedge \sim q)$ is false, then the truth values of p and q are respectively : 

     

    Consider the following three statements :
    (A) If $3+3=7$ then $4+3=8$.
    (B) If $5+3=8$ then earth is flat.
    (C) If both $(A)$ and $(B)$ are true then $5+6=17$.

    Then, which of the following statements is correct?

    The statement $\mathrm{p} \wedge(\sim \mathrm{p} \vee \mathrm{q})$ is equivalent to

    Choose the corect option for th following truth table : 

    $\begin{array}{|c|c|c|}
    \hline r & s & r \wedge s \\
    \hline T & T & (\mathrm{I}) \\
    \hline T & F & (\mathrm{II}) \\
    \hline F & T & (\mathrm{III}) \\
    \hline F & F & (\mathrm{IV}) \\
    \hline
    \end{array}$

    Choose the correct option for the following table : 

    $\begin{array}{|c|c|c|}
    \hline r & s & r v s \\
    \hline T & T & \text { (I) } \\
    \hline T & F & \text { (II) } \\
    \hline F & T & \text { (III) } \\
    \hline F & F & \text { (IV) } \\
    \hline
    \end{array}$

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    The expression $\sim \left ( \sim p\rightarrow q\right )$ is logically equivalent to : 

    $\sim (P \vee q ) =$

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    $p \vee q$  has the truth value F if 

    Concepts Covered - 0

    Relation Between Set Notation and Truth Table

    Sets can be used to identify basic logical structure of statements.

    Let us understand with an example of two sets p {1,2} and q {2,3}

    \begin{array}{|c|c|c|}\hline\quad p\vee q\quad & \quad p\cup q\quad&\quad 1,2,3\quad \\ \hline p\wedge q& p\cap q&2 \\ \hline p^c& \sim p & 3,4 \\ \hline q^c& \sim q&1,4 \\ \hline\end{array}

    Using this relation we get

    \begin{array}{|c|c|c|c|c|c|c|c|c|c|c|}\hline \text{Element } & \mathrm{\;\;\;\;\;}p\mathrm{\;\;\;\;\;}&\mathrm{\;\;\;}q\mathrm{\;\;\;}&\mathrm{\;\;\;\;\;}\sim p\mathrm{\;\;\;\;\;}&\mathrm{\;\;\;}\sim q\mathrm{\;\;\;} &\mathrm{\;\;\;}p\wedge q\mathrm{\;\;}&\mathrm{\;\;}p\vee q\mathrm{\;\;}&\sim\left (p\wedge q \right )\mathrm{\;\;}&\sim p\wedge\sim q\mathrm{\;\;} \\ \hline \hline 1& \mathrm{T}&\mathrm{F} & \mathrm{F} &\mathrm{T}&\mathrm{F}&\mathrm{T}&\mathrm{T}&\mathrm{F} \\ \hline2& \mathrm{T}&\mathrm{T} & \mathrm{F} &\mathrm{F}&\mathrm{T}&\mathrm{T}&\mathrm{F}&\mathrm{F} \\ \hline 3& \mathrm{F}&\mathrm{T} & \mathrm{T} &\mathrm{F}&\mathrm{F}&\mathrm{F}&\mathrm{T}&\mathrm{F} \\ \hline4& \mathrm{F}&\mathrm{F} & \mathrm{T} &\mathrm{T}&\mathrm{F}&\mathrm{F}&\mathrm{T}&\mathrm{T} \\ \hline\end{array}

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