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    JEE Main High Scoring Topics 2026 - Subject-Wise List

    Power - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Power is considered one of the most asked concept.

    • 34 Questions around this concept.

    Solve by difficulty

    A body of mass m  accelerates uniformly from rest to V  in time T  The instantaneous power delivered to the body as a function of time is given by : 

    A body of mass accelerates uniformly from rest   to v_{1}  in time t_{1}  The instantaneous power delivered to the body as a function of time t is :

    A body is moved along a straight line by a machine delivering constant power. The distance moved by the body in time t is proportional to:

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    Initially block of mass 2 kg was at rest. If variable force $F=(2 t-4) N$ acts on a block. Then find the average power delivered to the block for time interval $t=0 \mathrm{~s}$ to $\mathrm{t}=1 \mathrm{sec}$.

     A weight lifter lifts 300 kg from the ground to a height of 4m in 3 seconds. The average power generated by him is

    A body is moved along a straight line by a machine delivering constant power. The distance moved by the body in time t is proportional to 

    The position of a body changes with time as $x=t^2 \hat{i}+t \hat{j}$ due to force F. Then what will be power delivered by their force to the body as a function of time? [mass of body is 1 Kg ]

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    An object of mass 1000 g experiences a time-dependent force $\overrightarrow{\mathrm{F}}=\left(2 \mathrm{t} \hat{\mathrm{i}}+3 \mathrm{t}^2 \hat{\mathrm{j}}\right) \mathrm{N}$. The power generated by the force at time $t$ is :
     

    Concepts Covered - 1

    Power
    1. Definition-

    Power is defined as the rate at which work is done or energy is transferred.

    1. Dimension -

    $M L^2 T^{-3}$
    3. Units-
    - SI- Watt or Joule/sec
    - CGS- Erg/sec
    4. Average power-

    $$
    P_{a v}=\frac{\Delta w}{\Delta t}=\frac{\int_0^t p \cdot d t}{\int_0^t d t}
    $$

    5. Instantaneous power-

    $$
    P=\frac{d w}{d t}=P=\vec{F} \cdot \vec{v}
    $$


    Where, $\vec{F} \rightarrow$ force

    $$
    \vec{v} \rightarrow \text { velocity }
    $$

    i.e. power is equal to the scalar product of force with velocity
    6. Power expressed as the rate of change of kinetic Energy

    $$
    P=\frac{d k}{d t}
    $$


    Where, $d k \rightarrow$ change in kinetic energy

    $$
    d t \rightarrow \text { interval of time }
    $$
     

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