Careers360 Logo
JEE Main Registration 2025 Session 1, 2 - IIT Application Form Date, Fees, Documents Required

Conservative And Non-conservative Forces - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • 5 Questions around this concept.

Solve by difficulty

A ball of mass m = 3 Kg is being pulled from the ground on a fixed rough hemispherical surface up to the top of the hemisphere with the help of a light inextensible string. Find work (in Joule) done by tension M in the string if the radius of the hemisphere is R = 1 m and the friction coefficient is \mu = 0.6

Assume that the block is pulled with negligible velocity 

Concepts Covered - 1

Work Done in Conservative and Non-Conservative Field
  1. Conservative  field- 

  • In the conservative field, work done by the force depends only upon the initial and final position.

  • In the conservative field, work done by the force does not depend on the path.

  • In the conservative field, work done by the force along a closed path is zero.

  1. Conservative force-

  • The forces of these type of fields are known as conservative forces.

                      Example: Electrostatic forces, gravitational forces, the spring force

  1. Non-Conservative field-

  • In Non- conservative field, work done by the force depends on the path followed between any two positions/points.

  • In Non-conservative field, work done by the force along a closed path is non-zero.

  1. Non-Conservative Force-

  • The forces corresponding to Non-Conservative field are known as non-conservative forces.

  • Non-Conservative Force is dissipative.

                    Example: Frictional force, Viscous force

Study it with Videos

Work Done in Conservative and Non-Conservative Field

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Books

Reference Books

Work Done in Conservative and Non-Conservative Field

Physics Part II Textbook for Class XI

Page No. : 125

Line : 74

E-books & Sample Papers

Get Answer to all your questions

Back to top