Moment of inertia of a RING is considered one of the most asked concept.
8 Questions around this concept.
Moment of inertia of a circular wire of mass M and radius R about its diameter is
The moment of inertia of a ring along its diameter is
Let I=Moment of inertia of a RING about an axis through its centre and perpendicular to its plane
To find out I Consider a ring of mass M, radius R and centre O.

Take an elementary portion of the ring of mass dm and length dx.
So, $d I=d m \cdot R^2$
And,
$
I=\int d I=\int d m * R^2=R^2 \int d m=M R^2
$
"Stay in the loop. Receive exam news, study resources, and expert advice!"
This round of applications closing on 15th July | Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
100+ Recruiters | 1200+ Placements of 2026 Batch | NBA & NAAC Accredited | Highest CTC 37 LPA
NAAC A++ Grade | Highest Package-30 LPA | 400+ Recruiters
NAAC A+ Grade | Ranked 503 Globally (QS World University Rankings 2026)
40 LPA Highest Package | Up to 100% Scholarship worth 24 Crore via GUTS exam
Last Date to Apply: 15th July | Ranked #43 among Engineering colleges in India by NIRF | Get Upto 100% Scholarships | Spot Admissions via CUET
Explore on Careers360
Student Community: Where Questions Find Answers