Careers360 Logo
IIT Cut Off for BTech Ceramic Engineering 2025: Check Opening & Closing Rank

Moment Of Inertia Of A Rectangular Plate - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Moment of inertia for uniform rectangular lamina is considered one the most difficult concept.

  • 5 Questions around this concept.

Concepts Covered - 1

Moment of inertia for uniform rectangular lamina

Let I_{yy}=Moment of inertia for uniform rectangular lamina about y- axis passing through its centre .

                  

To calculate I_{yy}

Consider a uniform rectangular lamina of length l, and breadth b and mass M  

 mass per unit Area of  rectangular lamina = \sigma =\frac{M}{A}=\frac{M}{l*b}

 

Take a small element of mass dm with length dx at a distance x from the y-axis as shown in figure.

 

dm=\sigma dA=\sigma (bdx)

\Rightarrow dI= x^2dm

Now integrate this dI  between the limits  {\frac{-l}{2}} \ to \ {\frac{ l}{2}}

I_{yy}=\int dI=\int x^2dm=\int_{\frac{-l}{2}}^{\frac{l}{2}} \frac{M}{lb}x^2*( b)dx= \frac{M}{l}\int_{\frac{-l}{2}}^{\frac{l}{2}}x^2dx=\frac{Ml^2}{12}

 

Similarly 

Let I_{xx} = Moment of inertia for uniform rectangular lamina about x- axis passing through its centre .

To calculate I_{xx}

Take a small element of mass dm with length dx at a distance x from the x-axis as shown in figure.

mass per unit Area of  rectangular lamina = \sigma =\frac{M}{A}=\frac{M}{l*b}

dm=\sigma dA=\sigma (ldx)

\Rightarrow dI= x^2dm

Now integrate this dI  between the limits {\frac{-b}{2}} \ to \ {\frac{ b}{2}}

I_{xx}=\int dI=\int x^2dm=\int_{\frac{-b}{2}}^{\frac{b}{2}} \frac{M}{lb}x^2*( l)dx= \frac{M}{b}\int_{\frac{-b}{2}}^{\frac{b}{2}}x^2dx=\frac{Mb^2}{12}

 

Study it with Videos

Moment of inertia for uniform rectangular lamina

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Get Answer to all your questions

Back to top