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Moment Of Inertia Of A Rectangular Plate - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Moment of inertia for uniform rectangular lamina is considered one the most difficult concept.

  • 5 Questions around this concept.

Concepts Covered - 1

Moment of inertia for uniform rectangular lamina

Let I_{yy}=Moment of inertia for uniform rectangular lamina about y- axis passing through its centre .

                  

To calculate I_{yy}

Consider a uniform rectangular lamina of length l, and breadth b and mass M  

 mass per unit Area of  rectangular lamina = \sigma =\frac{M}{A}=\frac{M}{l*b}

 

Take a small element of mass dm with length dx at a distance x from the y-axis as shown in figure.

 

dm=\sigma dA=\sigma (bdx)

\Rightarrow dI= x^2dm

Now integrate this dI  between the limits  {\frac{-l}{2}} \ to \ {\frac{ l}{2}}

I_{yy}=\int dI=\int x^2dm=\int_{\frac{-l}{2}}^{\frac{l}{2}} \frac{M}{lb}x^2*( b)dx= \frac{M}{l}\int_{\frac{-l}{2}}^{\frac{l}{2}}x^2dx=\frac{Ml^2}{12}

 

Similarly 

Let I_{xx} = Moment of inertia for uniform rectangular lamina about x- axis passing through its centre .

To calculate I_{xx}

Take a small element of mass dm with length dx at a distance x from the x-axis as shown in figure.

mass per unit Area of  rectangular lamina = \sigma =\frac{M}{A}=\frac{M}{l*b}

dm=\sigma dA=\sigma (ldx)

\Rightarrow dI= x^2dm

Now integrate this dI  between the limits {\frac{-b}{2}} \ to \ {\frac{ b}{2}}

I_{xx}=\int dI=\int x^2dm=\int_{\frac{-b}{2}}^{\frac{b}{2}} \frac{M}{lb}x^2*( l)dx= \frac{M}{b}\int_{\frac{-b}{2}}^{\frac{b}{2}}x^2dx=\frac{Mb^2}{12}

 

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Moment of inertia for uniform rectangular lamina

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