17 Questions around this concept.
The equation of tangent to the ellipse $\frac{x^2}{50}+\frac{y^2}{32}=1$ which passes through a point $(15,-4)$ is
The values of $\lambda$ for which the line $y=2 x+\lambda_{\text {is a chord to hyperbola }} x^2-y^2-2 x+2 y-1=0$ is/are
Hyperbola : $\quad \frac{x^2}{a^2}-\frac{y^2}{b^2}=1$
Line: $\quad y=m x+c$
After solving Eq. (i) and Eq. (ii)
$
\begin{aligned}
& \quad \frac{x^2}{a^2}-\frac{(m x+c)^2}{b^2}=1 \\
& \Rightarrow \quad\left(a^2 m^2-b^2\right) x^2+2 \mathrm{mca}^2 x+c^2 a^2+a^2 b^2=0
\end{aligned}
$
Above equation is quadratic in $x$
The line will cut the hyperbola in two points may be real, coincident or imaginary, that depends on the value of Discriminant, D.
1. If $D>0$, then two real and distinct roots which means two real and distinct points of intersection of the line and the hyperbola. In this case, the line is secant (chord) to the hyperbola.
2. If $\mathrm{D}=0$, then equal real roots which means the line is tangent to the hyperbola. Solving $\mathrm{D}=0$ we get the condition for tangency, which is $c^2=a^2 m^2-b^2$
3. If $D<0$, then no real root which means the line and hyperbola do not intersect.

"Stay in the loop. Receive exam news, study resources, and expert advice!"
Coordinate Geometry (Arihant)
Page No. : 565
Line : 9
8156+ Downloads
6696+ Downloads
7805+ Downloads
4648+ Downloads
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Application Deadline: 15th April | Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
Mark presence in the Modern Architectural field with Bachelor of Architecture | Highest CTC : 70 LPA | Accepts NATA Score
Highest CTC 58 LPA | Avg CTC 11.35 LPA| 150+ Recruiters
Highest CTC 26 LPA | Top Recruiters: Accenture, TCS, Tech Mahindra, Capgemini, Microsoft
Integrated M.Tech admissions open @ VIT Bhopal University | Highest CTC 70 LPA | Application Closing Soon | Apply now
Explore on Careers360
Student Community: Where Questions Find Answers