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    How to Build an Effective Study Plan for JEE 2027: Expert Strategies for Consistent Performance

    Length of Intercept Cut-Off from a line - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

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    • 8 Questions around this concept.

    Solve by difficulty

    Find the X-intercept and Y-intercept of line 3x-4y + 12 = 0.

    Radius of the circle with centre $(3,-1)$ and cutting a chord of length 6 on the line $2 x-5 y+18=0$ is

    Concepts Covered - 1

    Length of Intercept Cut-Off from a line

    Length of Intercept Cut-Off from a line

    The length of the intercept cut off from the line $L: y=m x+c$ by the circle $x^2+y^2=a^2$ is

    $
    2 \times \sqrt{\left(\frac{a^2\left(1+m^2\right)-c^2}{\left(1+m^2\right)}\right)}
    $

    $
    \begin{aligned}
    & \mathrm{OM}=\left|\frac{\mathrm{c}}{\sqrt{1+\mathrm{m}^2}}\right| \\
    & \text { In } \Delta \mathrm{OAM}, \quad \mathrm{AM}^2=\mathrm{AO}^2-\mathrm{OM}^2 \\
    & =\mathrm{a}^2-\frac{\mathrm{c}^2}{1+\mathrm{m}^2} \\
    & =\frac{a^2\left(m^2+1\right)-c^2}{\left(1+m^2\right)} \\
    & \Rightarrow \quad \mathrm{AM}=\sqrt{\frac{\mathrm{a}^2\left(\mathrm{~m}^2+1\right)-\mathrm{c}^2}{\left(1+\mathrm{m}^2\right)}} \\
    & \text { Length of intercept is }=\mathrm{AB} \\
    & =2 \mathrm{AM} \\
    & \mathrm{AB}=2 \times \sqrt{\frac{\mathrm{a}^2\left(\mathrm{~m}^2+1\right)-\mathrm{c}^2}{\left(1+\mathrm{m}^2\right)}}
    \end{aligned}
    $
     

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    Length of Intercept Cut-Off from a line

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