JEE Main 2025 Topper Rajit Gupta Interview: "Happiness is the Key to My Success"

Kirchhoff's Second Law - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Kirchhoff's second law is considered one of the most asked concept.

  • 81 Questions around this concept.

Solve by difficulty

In the given circuit, with a steady current, the potential drop across the capacitor must be

The Kirchhoff’s first law $\left(\sum i=0\right)$ and second law $\left(\sum i R=\sum E\right)$ where the symbols have their usual meanings, are respectively based on

For the network shown below, the value of $V_B-V_A$ is __________$V$.

The given potentiometer has its wire of resistance $10 \Omega$. When the sliding contact is in the middle of the potentiometer wire, the potential drop across the $2 \Omega$ resistor is:

The magnitude and direction of the current in the circuit shown will be:

The value of R is 

Current flowing through the circuit is 

UPES B.Tech Admissions 2025

Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 28th April

ICFAI University Hyderabad B.Tech Admissions 2025

Merit Scholarships | NAAC A+ Accredited | Top Recruiters : E&Y, CYENT, Nvidia, CISCO, Genpact, Amazon & many more

If the current through the circuit is 2A. Find E.

The electric potential at O is

 

 

JEE Main 2025 College Predictor
Know your college admission chances in NITs, IIITs and CFTIs, many States/ Institutes based on your JEE Main rank by using JEE Main 2025 College Predictor.
Use Now

Concepts Covered - 1

Kirchhoff's second law

Kirchoff's second law

The algebraic sum of all the potential across a closed loop is zero. This law is also known as Kirchhoff's Voltage law (KVL)

  • Change in Potential in traversing a resistance is -iR

  • Change in Potential in the opposite direction is iR

  • Traversing an e.m.f source from negative to positive terminal is -E

  • While in the opposite direction is E

  • Change in Potential in traversing a capacitor from negative to positive $\frac{q}{C}$

  • While in the opposite direction is $-\frac{q}{C}$

 

 

 In closed-loop

$-i_1 R_1+i_2 R_2-E_1-i_3 R_3+E_2+E_3-i_4 R_4=0$

 

Study it with Videos

Kirchhoff's second law

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Get Answer to all your questions

Back to top