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Kirchhoff's Second Law - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Kirchhoff's second law is considered one of the most asked concept.

  • 37 Questions around this concept.

Solve by difficulty

In the above circuit the current (in A) in each resistance is :

 

A 5 V battery with internal resistance  $2 \Omega$ and a 2 V battery with internal resistance $1 \Omega$  are connected to a $10 \Omega$  resistor as shown in the figure. The current in the $10 \Omega$ resistor is

 

In the circuit shown, the current in the 1\Omega resistor is :

 

 How sign convention is taken during traversing of capacitor 

In this figure the resistance of the coil of galvanometer G is 2 \Omega . The emf of the cell is 4 V. The ratio of potential difference across C1 and C2 is:

In network shown in figure below the potential difference between \mathrm{A} and \mathrm{B} is

Find the current through the 30\; \Omega resistance in the circuit shown.

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In the circuit shown in figure, the current in 3 \Omega resistance is:

 

 

If galvanometer shows null deflection in the given figure then the value of Y is

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Concepts Covered - 1

Kirchhoff's second law

Kirchoff's second law

The algebraic sum of all the potential across a closed loop is zero. This law is also known as Kirchhoff's Voltage law (KVL)

  • Change in Potential in traversing a resistance is -iR

  • Change in Potential in the opposite direction is iR

  • Traversing an e.m.f source from negative to positive terminal is -E

  • While in the opposite direction is E

  • Change in Potential in traversing a capacitor from negative to positive $\frac{q}{C}$

  • While in the opposite direction is $-\frac{q}{C}$

 

 

 In closed-loop

$-i_1 R_1+i_2 R_2-E_1-i_3 R_3+E_2+E_3-i_4 R_4=0$

 

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Kirchhoff's second law

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