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Kirchhoff's second law is considered one of the most asked concept.
37 Questions around this concept.
In the above circuit the current (in A) in each resistance is :
A 5 V battery with internal resistance $2 \Omega$ and a 2 V battery with internal resistance $1 \Omega$ are connected to a $10 \Omega$ resistor as shown in the figure. The current in the $10 \Omega$ resistor is
In the circuit shown, the current in the 1 resistor is :
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How sign convention is taken during traversing of capacitor
In this figure the resistance of the coil of galvanometer G is . The emf of the cell is . The ratio of potential difference across and is:
In network shown in figure below the potential difference between and is
Find the current through the resistance in the circuit shown.
In the circuit shown in figure, the current in resistance is:
If galvanometer shows null deflection in the given figure then the value of Y is
Kirchoff's second law
The algebraic sum of all the potential across a closed loop is zero. This law is also known as Kirchhoff's Voltage law (KVL)
Change in Potential in traversing a resistance is -iR
Change in Potential in the opposite direction is iR
Traversing an e.m.f source from negative to positive terminal is -E
While in the opposite direction is E
Change in Potential in traversing a capacitor from negative to positive $\frac{q}{C}$
While in the opposite direction is $-\frac{q}{C}$
In closed-loop
$-i_1 R_1+i_2 R_2-E_1-i_3 R_3+E_2+E_3-i_4 R_4=0$
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