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Kirchhoff's Second Law - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Kirchhoff's second law is considered one of the most asked concept.

  • 81 Questions around this concept.

Solve by difficulty

In the given circuit, with a steady current, the potential drop across the capacitor must be

The Kirchhoff’s first law $\left(\sum i=0\right)$ and second law $\left(\sum i R=\sum E\right)$ where the symbols have their usual meanings, are respectively based on

For the network shown below, the value of $V_B-V_A$ is __________$V$.

The given potentiometer has its wire of resistance $10 \Omega$. When the sliding contact is in the middle of the potentiometer wire, the potential drop across the $2 \Omega$ resistor is:

The magnitude and direction of the current in the circuit shown will be:

The value of R is 

Current flowing through the circuit is 

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If the current through the circuit is 2A. Find E.

The electric potential at O is

 

 

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Concepts Covered - 1

Kirchhoff's second law

Kirchoff's second law

The algebraic sum of all the potential across a closed loop is zero. This law is also known as Kirchhoff's Voltage law (KVL)

  • Change in Potential in traversing a resistance is -iR

  • Change in Potential in the opposite direction is iR

  • Traversing an e.m.f source from negative to positive terminal is -E

  • While in the opposite direction is E

  • Change in Potential in traversing a capacitor from negative to positive $\frac{q}{C}$

  • While in the opposite direction is $-\frac{q}{C}$

 

 

 In closed-loop

$-i_1 R_1+i_2 R_2-E_1-i_3 R_3+E_2+E_3-i_4 R_4=0$

 

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Kirchhoff's second law

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