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Ionization And Electron Gain Enthalpy - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:35 AM | #JEE Main

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  • 6 Questions around this concept.

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For electron gain enthalpies of the elements denoted as \Delta_{\mathrm{eg}} \mathrm{H}, the incorrect option is :

The correct order of first ionization enthalpy values of the following elements is :

(A) O

(B) N

(C) Be

(D) F

(E) B

Choose the correct answer from the options given below :

Concepts Covered - 1

Ionization And Electron Gain Enthalpy

Ionization Energy and Electron Affinity

Ionization energy and electron affinity are defined at absolute zero. At any other temperature, heat capacities for the reactants and the products have to be taken into account.

$\begin{aligned} & \mathrm{M}(\mathrm{g}) \rightarrow \mathrm{M}^{+}(\mathrm{g})+\mathrm{e}^{-}(\text {for ionization }) \\ & \mathrm{M}(\mathrm{g})+\mathrm{e}^{-} \rightarrow \mathrm{M}^{-}(\mathrm{g}) \text { (for electron gain) }\end{aligned}$

at temperature, T is

$\Delta_r H^{\ominus}(T)=\Delta_r H^{\ominus}(0)+\int_0^T \Delta_r C_p^{\ominus} d T$

The value of Cp for each species in the above reaction is 5/2 R (CV = 3/2R)

So, $\Delta_r C_p^{\ominus}=+5 / 2 \mathrm{R}$ (for ionization) $\Delta_I C_p^{\ominus}=-5 / 2 \mathrm{R}$ (for electron gain)

Therefore,

$\Delta_r H^{\ominus}($ ionization enthalpy $)=E_0($ ionization energy $)+5 / 2 \mathrm{RT}$
$\Delta_r H^{\ominus}($ electron gain enthalpy $)=-\mathrm{A}($ electron affinity $)-5 / 2 \mathrm{RT}$

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Ionization And Electron Gain Enthalpy

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Ionization And Electron Gain Enthalpy

Chemistry Part I Textbook for Class XI

Page No. : 179

Line : 40

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