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Horizontal and Vertical Ellipse - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Horizontal and Vertical Ellipse is considered one the most difficult concept.

  • 43 Questions around this concept.

Solve by difficulty

Consider an ellipse, whose centre is at the origin and its major axis is along the x-axis.  If its eccentricity is \small \frac{3}{5}  and the distance between its foci is 6, then the area (in sq. units) of the quadrilateral inscribed in the ellipse, with the vertices as the end points of major and minor axes of ellipse, is

 

The equation of the ellipse whose axes are the axes of coordinates and which passes through the point (–3, 1) and has eccentricity \sqrt{\frac{2}{5}}   is

Concepts Covered - 1

Horizontal and Vertical Ellipse

Horizontal and Vertical Ellipse

When the major axis is along Y-axis and the minor axis is along X-axis, i.e. b > a

Then, AA’ = 2a and BB’ = 2b

The foci are S (0, be) and S’(0, be)

The equation of directrix MZ and M’Z’ are \\\mathrm{y=\frac{b}{e}\;\;\;and\;\;y=-\frac{b}{e}}

Equation

                \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 ; a>b

\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 ; a<b

Graph

Centre

(0 ,0)

(0, 0)

Vertices

(\pm \mathrm{a}, 0)

(0, \pm \mathrm{b})

Length of Major Axis

2a

2b

Length of Minor Axis

2b

2a

Foci

(\pm \mathrm{ae}, 0)

(0, \pm \mathrm{be})

Distance b/w foci

2ae

2be

Equation of Directrices

\mathrm{x}=\pm \frac{\mathrm{a}}{\mathrm{e}}

y=\pm\frac{b}{e}

Distance b/w Directrices

\frac{2 \mathrm{a}}{\mathrm{e}}

\frac{2 \mathrm{b}}{\mathrm{e}}

Eccentricity, e

\mathrm{e}=\sqrt{1-\frac{\mathrm{b}^{2}}{\mathrm{a}^{2}}}

\mathrm{e}=\sqrt{1-\frac{\mathrm{a}^{2}}{\mathrm{b}^{2}}}

Length of Latusrectum

\frac{2 \mathrm{b}^{2}}{\mathrm{a}}

\frac{2 \mathrm{a}^{2}}{\mathrm{b}}

Endpoint of Latusrectum

\left(\pm \mathrm{ae}, \pm \frac{\mathrm{b}^{2}}{\mathrm{a}}\right)

\left(\pm \frac{\mathrm{a}^{2}}{\mathrm{b}}, \pm \mathrm{be}\right)

Focal radii

SP+S'P = 2a

SP+S'P = 2b

Parametric coordinates

{\color{Blue} (a \cos \theta, b \sin \theta) \quad 0 \leq \theta \leq 2 \pi }

{\color{Blue} (a \cos \theta, b \sin \theta) \quad 0 \leq \theta \leq 2 \pi }

Tangent at vertices

\mathrm{x}=\pm \mathrm{a}

y=\pm b

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Horizontal and Vertical Ellipse

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