Careers360 Logo
JEE Main Chemistry High Weightage Chapters and Topics 2025

Force Between Two Parallel Current Carrying Conductors - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Force between two parallel current carrying infinite wires is considered one the most difficult concept.

  • 29 Questions around this concept.

Solve by difficulty

Two long conductors, separated by a distance d carry current I_{1}\; and \; I_{2}   in the same direction.They exert a force  F on each other Now the current in one of them is increased to two times and its direction is reversed. The distance is also increased to 3d. The new value of the force between them is

Two thin long, parallel wires, separated by a distance d carry a current of  i  A in the same direction. They will

 

Two long straight parallel wires, carrying (adjustable) currents I1 and I2, are kept at a distance d apart. If the force ‘F’ between the two wires is taken as ‘positive’ when the wires repel each other and ‘negative’ when the wires attract each other, the graph showing the dependence of ‘F’, on the product  I1I2,  would be :

Two concentric coils each of radius equal to  2\pi cm are placed at right angles to each other. 3 ampere and 4 ampere are the currents flowing in each coil respectively. The magnetic induction in weber/m2  at the center of the coils will be

(\mu_{0} =4\pi \times 10^{-7}\; Wb/A-m)

Concepts Covered - 1

Force between two parallel current carrying infinite wires

Force between two parallel current carrying infinite wires-

Let us take two long straight conductors carrying currents i_1and i_2 placed parallel to each other at a distance ‘a’ from each other as shown in the figure - 

                                                                                         

Now, from the earlier concept which we have studied before, we can say that the conductor 2 experiences the some magnetic field at every point along its length due to the conductor 1. Because of this there will be some force acting on conductor 2 and the direction of magnetic force is indicated in the figure and it can be visualised by using the right-hand thumb rule. 

                                                                            

Now, if we apply Ampere's circuital law on the first conductor then the magnitude of the magnetic field can be obtained as -

                                                                             B_{1}=\frac{\mu_{0} I_{1}}{2 \pi a} 

Then the force on a segment of length L of the conductor 2 due to the conductor 1 can be given as,

                                                                 F_{21}=I_{2} L B_{1}=\frac{\mu_{0} I_{1} I_{2}}{2 \pi a} L

Similarly, we can calculate the force exerted by the conductor 2 on the conductor 1. We see that, the conductor 1 experiences the same force due to the conductor 2 but the direction of force is opposite. Thus we can say that, 

                                                                                     F_{21} = F_{12}                 (But the direction will be opposite.) 

But if the direction of current flowing through the conductor is opposite in both the conductors then both the wire will repel each other.

Also, the magnitude of force acting per unit length can be given as - 

                                                                                  f_{12}=f_{21} = \frac{\mu_{0} I_{1} I_{2}}{2 \pi a}

Study it with Videos

Force between two parallel current carrying infinite wires

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Get Answer to all your questions

Back to top