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Current Given by a Cell is considered one the most difficult concept.
27 Questions around this concept.
The maximum current through a cell of internal resistance $0.1\Omega$ and e.m.f 2V is
The potential drop inside a cell of internal resistance $0.5\Omega$ is found to be 2V. The current through the cell is
Current supplied by the cell
Cell supplies a constant current in the circuit.
$
i=\frac{E}{R+r}
$
$R$ - External resistance
$r$ - internal resistance
- Potential drop inside the cell=ir
- The internal resistance of the cell
$
r=\left(\frac{E}{V}-1\right) R
$
- Power dissipated in external resistance
$
P=\left(\frac{E}{R+r}\right)^2 R
$
- Maximum power is obtained when the resistance value of the load is equal in value to that of the voltage sources internal resistance.
Maximum power
$
P_{\max }=\frac{E^2}{4 r}
$
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