Current Given by a Cell is considered one the most difficult concept.
34 Questions around this concept.
The maximum current through a cell of internal resistance $0.1\Omega$ and e.m.f 2V is
The potential drop inside a cell of internal resistance $0.5\Omega$ is found to be 2V. The current through the cell is
To verify Ohm’s law, a student connects the voltmeter across the battery as shown in the figure. The measured voltage is plotted as a function of the current and the following graph is obtained. If Vo is almost zero, then identify the correct statement.
New: JEE Main 2026 Registration Link | Top 30 Most Repeated Questions
JEE Main Prep: Study Plan | Preparation Tips | High Scoring Chapters and Topics
JEE Main QP & Mock: Previous 10 Year Questions | Chapter Wise PYQs | Mock test Series
JEE Main Most Scoring Concept: January 2025 Session | April 2025 Session
Why is the terminal voltage of a cell generally less than the emf of the cell?
Current supplied by the cell

Cell supplies a constant current in the circuit.
$
i=\frac{E}{R+r}
$
$R$ - External resistance
$r$ - internal resistance
- Potential drop inside the cell=ir
- The internal resistance of the cell
$
r=\left(\frac{E}{V}-1\right) R
$
- Power dissipated in external resistance
$
P=\left(\frac{E}{R+r}\right)^2 R
$
- Maximum power is obtained when the resistance value of the load is equal in value to that of the voltage sources internal resistance.
Maximum power
$
P_{\max }=\frac{E^2}{4 r}
$
 
"Stay in the loop. Receive exam news, study resources, and expert advice!"
