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Compound Microscope is considered one of the most asked concept.
9 Questions around this concept.
A compound microscope has an eyepiece of focal length and an objective of focal length . Calculate the magnification, if an object is kept at a distance of from the objective, so that the final image is formed at the least distance of distinct vision :
A compound microscope has an eyepiece of focal length and an objective of focal length . Calculate the magnification, if an object is kept at a distance of from the objective so that the final image is formed at the least distance of distinct vision :
In a compound microscope, the focal lengths of two lenses are and . If an object is placed at from objective and the final image is formed at from the eye lens, the distance between the two lenses is:
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Compound Microscope:
A compound microscope is of two converging lenses called objective and eye lens. It is used to view magnified images of small objects on a glass slide. It can achieve higher levels of magnification than stereo or other low power microscopes and reduce chromatic aberration.
Intermediate image is real and enlarged. The final image is magnified, virtual and inverted.
Here in the diagram
= Distance of object from objective (o),
= Distance of image (A′B′) formed by objective from objective,
= Distance of A′B′ from eye lens,
= Distance of final image from eye lens,
= Focal length of objective,
= Focal length of eye lens.
Case 1: Final image is formed at D : Magnification and length of the microscope tube (distance between two lenses) is
Generally, object is placed very near to the principal focus of the objective hence The eye piece is also of small focal length and the image formed by the objective is also very near the eyepiece.
So the length of the tube.
Hence, we can write
.
Case 2: Final image is formed at Magnification
In terms of length .
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