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    Bronsted Lowry and Lewis Acid-Base theory - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:35 AM | #JEE Main

    Quick Facts

    • Bronsted Lowry and Lewis Acid-Base theory is considered one the most difficult concept.

    • 46 Questions around this concept.

    Solve by difficulty

    Which of the following is a Lewis acid?

    Four species are listed below :

    (i)\; HCO^{-}_{3}\; \; \; \; \; \; \; \; \; \; \; (ii)\; H_{3}O^{+}

    (iii)\; HSO^{-}_{4}\; \; \; \; \; \; \; \; \; (iv)\; HSO_{3}F

    Which one of the following is the correct sequence of their acid strength?

    Identify the amphoteric species from the following :

     

    (I) $\mathrm{H}_2 \mathrm{O}$
    (II) $\mathrm{NH}_3$
    (II) $\mathrm{H}_2 \mathrm{PO}_4^{-}$
    (IV) $\mathrm{HCO}_3^{-}$

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    Which one of the following molecular hydrides acts as a Lewis acid?

    Which of the following is strongest Bronsted base ?

    According to Brosted H2O behave like 

    Conjugate base of H2O will be : 

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    Correct pair of Lewis acid and Lewis base respectively .

    For which of the following acid its conjugate base  will weak 

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    Species acting as both Bronsted Acid and base is :

    Concepts Covered - 2

    Bronsted Lowry and Lewis Acid-Base theory

    Bronsted-Lowry Acids and Bases

    According to this concept, an acid and a base can defined as follows :
    Acid: It is a substance that can donate a proton.
    Base: It is a substance that can accept a proton.

    Some examples include:

    • When HCl is dissolved in water, it donates a proton to H2O which behaves as a base.
      \mathrm{HCl}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{Cl}^{-}(\mathrm{aq})+\mathrm{H}_{3} \mathrm{O}^{-}(\mathrm{aq})
    • When HCO3is dissolved in water, it donates a proton to NH3 which behaves as a base.
      \mathrm{HCO}_{3}^{-}(\mathrm{aq})+\mathrm{NH}_{3}(\mathrm{aq}) \rightleftharpoons \mathrm{CO}_{3}^{2-}(\mathrm{aq})+\mathrm{NH}_{4}^{+}(\mathrm{aq})

    The base formed from an acid is known as the conjugate base of the acid. Correspondingly, the acid formed from a base is called the conjugate acid of the base.
    \mathrm{HCl+N H_{3} \rightleftharpoons C l^{-}+N H_{4}^{+}}
    In the above reaction, Cl- is the conjugate base of HCl and NH4is the conjugate acid NH3.

    Strength of Bronsted-Lowry Acid and Bases:
    The strength of an acid or base is measured by its tendency to lose or gain proton. A strong acid is a substance which loses a proton easily to a base. Consequently, the conjugate base of a strong acid is a weak base.

    The ability of an acid to lose a proton is experimentally measured by its equilibrium constant know as Ka. The larger the value of Ka, the more complete reaction or higher the concentration of H3O+ and the stronger is the acid. Similarly, for bases, we have the equilibrium constant, Kb which determines the extent of the completion of the reaction.

    Amphiprotic Compounds:
    The compounds which can act either as acids or as bases, NaSH, NaHCO3 etc are some of the examples.

     

    Lewis Acid and Bases:
    Acid: It is a substance that can form a covalent bond by accepting a shared pair of electrons.
    Base: It is a substance that possess at least one unshared pair of electrons.

    Substance that are bases in the Bronsted sysem are also bases according to the Lewis concept. However the Lewis definition of an acid considerably expands that number of substances that are classified as acid. A Lewis acid must have an empty orbital capable of receiving the electron pair of the base.
    Lewis acids include molecules or atoms that have incomplete octets. For example molecules like BF3, AlCl3, etc. act as Lewis Acid.

    Many simple cations can act as Lewis acids:
    \mathrm{Cu}^{2+}+4 \mathrm{NH}_{3} \rightarrow \mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}^{2+}

    Some metal atoms can function as acids in the formation of compounds such as:
    \mathrm{Ni}\: +\: 4\mathrm{C}\mathrm{O} \rightarrow \mathrm{Ni}(\mathrm{CO})_{4}

    Compounds that have central atoms capable of expanding their valence shells are Lewis acids in reactions in which this expansion occurs.
    \mathrm{SnCl}_{4}+2 \mathrm{Cl}^{-} \rightarrow \mathrm{SnCl}_{6}^{2-}

    Ionisation Constant of Acids and Bases and pH of strong Acids and Bases

    Ionisation constant of acid is also known as dissociation constant or equilibrium constant at the dissociation of acid. Thus, the ionisation constant equation of acid is given as follows:

    \mathrm{K_{a}\: =\: K_{c}\: =\: \frac{[H+][A^{-}]}{[HA]}}

    Thus, Ka is very small for weak acids and it is very high for strong acids. For example:

    \\\mathrm{HCl\: \rightarrow \: H^{+}\:+\: Cl^{-}}\\\\\mathrm{Thus,\: K_{a}\: =\: K_{c}\: =\: \frac{[H+][Cl^{-}]}{[HCl]}}
    Since HCl concentration is low after the reaction due to 100% dissociation, Ka for Strong acids is very high.

    Hence, as Ka increases, the strength of acid increases.

    Similarly, for bases we have:

    \mathrm{MOH \rightleftharpoons M^++O H^{-}}

    Again, the equilibrium constant Kb or Kc is given as follows:

    \mathrm{K_{b}\: =\: K_{c}\: =\: \frac{[M]^{+}[OH]^{-}}{[MOH]}}

    Again, Kb is very small for weak bases and it is very high for strong bases like NaOH. 

    Hence, as Kb increases, the strength of base increases.

     

    pH and Strong Acids/Bases

    pH is also referred to as potential or power of hydrogen. Mathematically, it can be represented as follows:

    \mathrm{pH\: =\: -log_{10}[H^{+}]}

    If solution is neutral, then:
    \mathrm{k_w = [H^+][OH^-]=10^{-14}}
    On Solving we have, 

    \mathrm{[H^+]=[OH^-]=10^{-7}}
    \mathrm{Thus, \ pH = 7}

    For Acidic solutions:                                                                                For Basic solutions:
    For acidic solutions, we must have \mathrm{[H^+] > [OH^-] }                                For basic solutions, we must have \mathrm{[H^+] < [OH^-] }
    Thus, \mathrm{[H^+] > 10^{-7} }                                                                                  Thus, \mathrm{[H^+] < 10^{-7} }
    Thus, \mathrm{[H^+] } for acids can be 10-6, 10-5, 10-4, etc.                                      Thus, \mathrm{[H^+] } for bases can be 10-8, 10-9, 10-10, etc.
    Thus, pH of acids can be 6, 5, 4, etc.                                                          Thus, pH of basics can be 8, 9, 10, 11, etc.
    Hence, pH of acidic solutions is less than 7                                                  Hence, pH of basic solutions is greater than 7

    pH of Strong Acids
    Strong acids are those acids which dissociate completely in solutions. For example:

    • 2 x 10-3 M HNO3
      Since HNO3 is a strong acid, thus it will dissociate completely into H+ and OH- ions as follows:

      \\\mathrm{HNO_{3}\: \rightarrow \: H^{+}\: +\: NO_{3}^{-}}\\\\\mathrm{Thus,\: [H^{+}]\: =\: 2\: x\: 10^{-3}M\: \: \: \: \: \: \: \: \: (given)}\\\\\mathrm{\Rightarrow\: pH\: =\: -log_{10}(2\: x\: 10^{-3})}\\\\\mathrm{\Rightarrow\: pH\: =\: -log_{10}(2)\: -\: log_{10}(10^{-3})}\\\\\mathrm{\Rightarrow\: pH\: =\: -0.30\: +\: 3\: =\: 2.7}
      Thus, pH of HNO3 is 2.7

     

    • 10-4 M H2SO4
      Since H2SO4 is a strong acid, thus it will dissociate completely into H+ and OH- ions as follows:

      \\\mathrm{H_{2}SO_{4}\: \rightarrow \: 2H^{+}\: +\: SO_{4}^{2-}}\\\\\mathrm{Thus,\: [H^{+}]\: =\: 2\: x\: 10^{-4}M\: \: \: \: \: \: \: \: \: (given)}\\\\\mathrm{\Rightarrow\: pH\: =\: -log_{10}(2\: x\: 10^{-4})}\\\\\mathrm{\Rightarrow\: pH\: =\: -log_{10}(2)\: -\: log_{10}(10^{-4})}\\\\\mathrm{\Rightarrow\: pH\: =\: -0.30\: +\: 4\: =\: 3.7}
      Thus, pH of H2SO4 is 3.7

    Study it with Videos

    Bronsted Lowry and Lewis Acid-Base theory
    Ionisation Constant of Acids and Bases and pH of strong Acids and Bases

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    Books

    Reference Books

    Bronsted Lowry and Lewis Acid-Base theory

    Chemistry Part I Textbook for Class XI

    Page No. : 214

    Line : 22

    Ionisation Constant of Acids and Bases and pH of strong Acids and Bases

    Chemistry Part I Textbook for Class XI

    Page No. : 219

    Line : 30

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