Amity University-Noida B.Tech Admissions 2026
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
23 Questions around this concept.
The thermodynamic process is shown below on a PV diagram for one mole of an ideal gas.If $\mathrm{} \mathrm{V}_2=2 \mathrm{~V}_1$ then the ratio of temperature $\frac{T_2}{T_1}$ is :
An ideal gas undergoes a quasi-static, reversible process in which its molar heat capacity C remains constant. If during this process the relation of pressure P and volume V is given by PVn=constant, then n is given by (Here CP and CV are molar specific heat at constant pressure and constant volume, respectively)
An ideal gas follows a process equation $\mathrm{PT}=$ constant. The correct graph between pressure and volume of gas is
Latest: Free All-India JEE Main 2026 Mock Test - Attempt Now
JEE Main Sample Papers: Physics | Chemistry | Maths | Top 30 Repeated Questions
JEE Main QP & Mock: Previous 10 Year Questions | Chapter Wise PYQs | Mock test Series
JEE Main Most Scoring Concept: January 2025 Session | April 2025 Session | Overall
An ideal monoatomic gas undergoes a process in which its internal energy U varies with its volume V according to relation $U=K V^{3 / 2}$, where K is a positive constant. If the molar-specific heat of the gas for this process is $\frac{N R}{3}$, then N is $\qquad$ -
A cylinder contain 1 mole of He gas of 200K.Pa and 27oC. The gas is compressed reversibly to a pressure of 600K.Pa following a polytropic process with exponent n=1.3. Then calculate the work required during the process.
For polytropic process $\left(P V^n=\right.$ constant $)$ n can take value as.
0.02 moles of an ideal diatomic gas with initial temperature $20^{\circ} \mathrm{C}$ is compressed from $1500 \mathrm{~cm}^3$ to $500 \mathrm{~cm}^3$. The thermodynamic process is such that $P V^2=\beta {\text {where }} \beta$ is constant. Then the value of $\beta$ is close to: (The gas constant $R=8.31 \mathrm{~J} / \mathrm{K} / \mathrm{mol}$ )
(A) $7.5 \times 10^{-2}$ Pa.m. ${ }^6$
(B) $1.5 \times 10^{-2}$ Pa.m. ${ }^6$
(C) $3 \times 10^{-2}$ Pa.m. ${ }^6$
(D) $2.2 \times 10^{-2}$ Pa.m. ${ }^6$
An ideal gas follows a process described by $P V^2=C$ from $\left(P_1, V_1, T_1\right)_{\text {to }}\left(P_2, V_2, T_2\right)$ (C is a constant). Then
An ideal gas with heat capacity at constant volume CV undergoes a quasistatic process described by PVα in a P-V diagram, where α is a constant. The heat capacity of the gas during this process is given by
A real gas within a closed chamber at $27^{\circ} \mathrm{C}$ undergoes the cyclic process as shown in figure. The gas obeys $P V^3=\mathrm{RT}$ equation for the path $A$ to $B$. The net work done in the complete cycle is (assuming $R=8 \mathrm{~J} / \mathrm{molK}$ ):
A process $P V^N=C$ is called polytropic process. So, any process in this world related to thermodynamics can be explained by polytropic process.
For example - 1. If $\mathrm{N}=1$, then the process become isothermal.
2. If $\mathrm{N}=0$, then the process become isobaric.
3. If $\mathrm{N}=\gamma$, then the process become adiabatic
Work done by the polytropic process -
$
W_{1-2}=\int P d V
$
For a polytropic process,
$
\begin{gathered}
P V^N=P_1 V_1^N=P_2 V_2^N=C \\
P=\frac{C}{V^N}
\end{gathered}
$
Substituting in Equation, we get,
$
\begin{aligned}
\int P d V & =\int \frac{C d V}{V^N}=C \int V^{-N} d v \\
& =\left[V^{1-N}\right]_1^2=\left(V_2^{1-N}-V_1^{1-N}\right) \\
W_{1-2} & =\frac{P_2 V_2-P_1 V_1}{1-N} \text { or } \frac{P_1 V_1-P_2 V_2}{N-1} \ldots \ldots (1)\\
P_1 V_1 & =n R T_1 \\
P_2 V_2 & =n R T_2
\end{aligned}
$
So, equation (1) can be written as -
$
W_{1-2}=\frac{n R\left(T_2-T_1\right)}{1-N}
$
And for one mole, $W_{1-2}=\frac{R\left(T_2-T_1\right)}{1-N}$
Specific heat for polytropic process -
We can write the equation of heat as - $Q=C \Delta T$
Here C = Molar specific heat -
From the first law of thermodynamics
$
\begin{aligned}
& \quad Q=\Delta U+W \\
& \text { or } C \Delta T=C_v \Delta T-\frac{R \Delta T}{(N-1)} \\
& \therefore \quad C=C_v-\frac{R}{(N-1)}=\frac{R}{(\gamma-1)}-\frac{R}{(N-1)}
\end{aligned}
$
"Stay in the loop. Receive exam news, study resources, and expert advice!"
