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    JEE Main High Scoring Topics 2026 - Subject-Wise List

    Isothermal Process - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • 36 Questions around this concept.

    Solve by difficulty

    In the given diagram graph 1 represents the adiabatic process and 2 represents the isothermal process. Which of the following comparisons is not true for graphs 1 and 2

     

    The Thermodynamic process, in which the internal energy of the system remains constant is

     For the P-V diagram given for an ideal gas,

    out of the following which one correctly represents the T-P diagram ?

     

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    For O2 gas while performing isothermal process the slope of P - V curve was =5 at state A. What is the slope of P - V curve at state A if same gas will perform adiabatic process?

    Match List - I with List - II.

      List - I   List - II
    (A) Isobaric (I) $\Delta \mathrm{Q}=\Delta W$
    (B) Isochoric (II) $\Delta Q=\Delta U$
    (C) Adiabatic (III) $\Delta Q=$ zero
    (D) Isothermal (IV) $\Delta Q=\Delta U+P \Delta V$

    $\Delta Q=$ Heat supplied
    $\Delta W=$ Work done by the system
    $\Delta U=$ Change in internal energy
    $P=$ Pressure of the system
    $\Delta V=$ Change in volume of the system
    Choose the correct answer from the options given below:

    Concepts Covered - 1

    Isothermal Process

    Isothermal process - When a thermodynamic system undergoes a thermodynamic process in such a way that its temperature remains constant, then that process is called an Isothermal process.

    So, $\mathrm{T}=$ constant and $\Delta T=0$.

    Trick to recognize isothermal process -
    - The walls of the container must be perfectly conducting (no resistance) which allows the exchange of heat between the gas and surroundings.
    - The process of compression or expansion should be infinitely slow so that the process gets proper time for the exchange of heat.

    Equation of isothermal process -
    As we know that the equation of state is given by $-P V=n R T$
    If $\mathrm{T}=$ constant and for a particular amount of gas ' $n$ ' is also constant.
    So we can write that - P.V $=$ Constant

     


     

    Points in graph of isothermal process - 

    i) Curves obtained on P-V graph are called isotherms and the graphs are hyperbolic in nature.

    ii) Slope of isothermal curve : 

         By differentiating PV = C

      

    $$
    \begin{gathered}
    P d V+V d P=0 \Rightarrow P d V=-V d P \Rightarrow \frac{d P}{d V}=-\frac{P}{V} \\
    \tan \theta=\frac{d P}{d V}=\frac{-P}{V}
    \end{gathered}
    $$

    iii) The area between the isothermal curve and volume axis represents the work done in the isothermal process.

    The formula of Work done in the isothermal process -

    $$
    \begin{aligned}
    & W=n R T \log _e\left(\frac{V_f}{V_i}\right)=2.303 n R T \log _{10}\left(\frac{V_f}{V_i}\right) \\
    & W=n R T \log _e\left(\frac{P_i}{P_f}\right)=2.303 n R T \log _{10}\left(\frac{P}{P_f}\right)
    \end{aligned}
    $$
     

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    Isothermal Process

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