JEE Main Result 2025 Session 2 - Date, Direct Link, BE, BTech Scorecard at jeemain.nta.nic.in

Isothermal Process - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • 33 Questions around this concept.

Solve by difficulty

In the given diagram graph 1 represents the adiabatic process and 2 represents the isothermal process. Which of the following comparisons is not true for graphs 1 and 2

 

The Thermodynamic process, in which the internal energy of the system remains constant is

 For the P-V diagram given for an ideal gas,

out of the following which one correctly represents the T-P diagram ?

 

For O2 gas while performing isothermal process the slope of P - V curve was =5 at state A. What is the slope of P - V curve at state A if same gas will perform adiabatic process?

Concepts Covered - 1

Isothermal Process

Isothermal process - When a thermodynamic system undergoes a thermodynamic process in such a way that its temperature remains constant, then that process is called an Isothermal process.

So, $\mathrm{T}=$ constant and $\Delta T=0$.

Trick to recognize isothermal process -
- The walls of the container must be perfectly conducting (no resistance) which allows the exchange of heat between the gas and surroundings.
- The process of compression or expansion should be infinitely slow so that the process gets proper time for the exchange of heat.

Equation of isothermal process -
As we know that the equation of state is given by $-P V=n R T$
If $\mathrm{T}=$ constant and for a particular amount of gas ' $n$ ' is also constant.
So we can write that - P.V $=$ Constant

 


 

Points in graph of isothermal process - 

i) Curves obtained on P-V graph are called isotherms and the graphs are hyperbolic in nature.

ii) Slope of isothermal curve : 

     By differentiating PV = C

  

$$
\begin{gathered}
P d V+V d P=0 \Rightarrow P d V=-V d P \Rightarrow \frac{d P}{d V}=-\frac{P}{V} \\
\tan \theta=\frac{d P}{d V}=\frac{-P}{V}
\end{gathered}
$$

iii) The area between the isothermal curve and volume axis represents the work done in the isothermal process.

The formula of Work done in the isothermal process -

$$
\begin{aligned}
& W=n R T \log _e\left(\frac{V_f}{V_i}\right)=2.303 n R T \log _{10}\left(\frac{V_f}{V_i}\right) \\
& W=n R T \log _e\left(\frac{P_i}{P_f}\right)=2.303 n R T \log _{10}\left(\frac{P}{P_f}\right)
\end{aligned}
$$
 

Study it with Videos

Isothermal Process

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Get Answer to all your questions

Back to top