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JEE Mains 2025 April 4 Shift 2 Answer Key – Download PDF with Solutions

Isochoric Process - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

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  • 20 Questions around this concept.

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In an isochoric process, if T_1 = 27 ^{\circ}C\: \: and \: \: T_2 = 127 ^{\circ}C. Then P_1 / P_2  will be equal to 

Which of them is a thermodynamic process


 

Concepts Covered - 1

Isochoric Process

Isochoric Process- A Thermodynamic process in which volume remains constant is known as the Isochoric Process.

In this process P and T changes keeping P constant. So Gay-Lussac’s law is obeyed in this process.

  Key points in the Isochoric Process 

  •  Its Equation of state is given as PT= constant

     or P1T1=P2T2= constant 

    - P-V Indicator diagram for an isobaric process

    Its PV graph has slope= infinity (i.e dPdV=,

 

The above Graph represents an Isochoric increase in pressure at volume V.

 The P-V diagram for this process is a  line is parallel to the pressure line.

  • Specific heat of gas during Isochoric process is given by

     

CV=f2R

- The bulk modulus of elasticity during Isochoric process is given by

K=ΔPΔV/V=ΔP0=

- Work done in Isochoric process-

ΔW=PΔV and as ΔV=0 So ΔW=0

- Internal energy in Isochoric process

ΔU=nCVΔT=nR(γ1)ΔT

- Heat in Isochoric process

From FLTD ΔQ=ΔU+ΔW
But ΔW=0

ΔQ=ΔU=nCVΔT=nR(γ1)ΔT=PfVfPiViγ1
 

  • Examples of Isochoric process-

  1. Heating of water in a pressure cooker (Valve closed)

 

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Isochoric Process

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