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Isochoric Process - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

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  • 11 Questions around this concept.

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In an isochoric process, if T_1 = 27 ^{\circ}C\: \: and \: \: T_2 = 127 ^{\circ}C. Then P_1 / P_2  will be equal to 

For this P- V indicator diagram which statement is not true 

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Concepts Covered - 1

Isochoric Process

Isochoric Process- A Thermodynamic process in which volume remains constant is known as the Isochoric Process.

In this process P and T changes keeping P constant. So Gay-Lussac’s law is obeyed in this process.

  Key points in the Isochoric Process 

  • Its Equation of state is given as \frac{P}{T}=constant

               or  \frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}=\text { constant }

  • P-V Indicator diagram for an isobaric process

       Its PV graph has slope= infinity (i.e \frac{dP}{dV}=\infty)

 

The above Graph represents an Isochoric increase in pressure at volume V.

 The P-V diagram for this process is a  line is parallel to the pressure line.

  • Specific heat of gas during Isochoric process is given by

              C_V=\frac{f}{2}R

  • The bulk modulus of elasticity during Isochoric process is given by

           K=\frac{\Delta P}{-\Delta V / V}= \frac{\Delta P}{0}= \infty

  • Work done in Isochoric process-

                \\ \Delta W=P\Delta V\\ \ and \ as \ \Delta V=0\\ So \ \Delta W=0

 

  • Internal energy in Isochoric process

           \Delta U=n C_{V} \Delta T=n\frac{R}{(\gamma-1)} \Delta T

  • Heat in Isochoric process

From FLTD  \Delta Q=\Delta U+\Delta W

But \Delta W=0

So \Delta Q=\Delta U=n C_{V} \Delta T=n\frac{R}{(\gamma-1)} \Delta T=\frac{P_fV_f-P_iV_i}{\gamma -1}

  • Examples of Isochoric process-

  1. Heating of water in a pressure cooker (Valve closed)

 

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Isochoric Process

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Isochoric Process

Physics Part II Textbook for Class XI

Page No. : 312

Line : 48

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