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    Law of Equivalence - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • 23 Questions around this concept.

    Solve by difficulty

    The volume of 0.02 M aqueous HBr required to neutralize 10.0 mL of 0.01 M aqueous \mathrm{Ba\left ( OH \right )_{2}} is (Assume complete neutralization)

    Calculate the normality of NaOH when 2g is present in 800 ml solution.

     

    Concepts Covered - 1

    Law of Equivalence

    Laws of Equivalence
    According to the law of equivalence, for each and every reactant and product, 
    Equivalents of each reactant reacted = Equivalents of each product formed.

    Example,
    Suppose the reaction is taking place as follows: 
    P\, +\, Q\rightarrow R\, +\, S 

    According to the law of equivalence, 

    Equivalents of P reacted = Equivalents of Q reacted = Equivalents of R produced = Equivalents of S produced 

    Equivalents of any substance = (Weight of substance (in g)) / (Equivalent weight)
    = Normality (N) x Volume (V) (In litre) 
    Normality (N) = n-Factor x Molarity (M) 

    Law of Equivalence finds great importance in Acid base Neutralisation Reactions as well as Redox Titrations.

    Here we shall be mainly covering the Acid Base neutralisation reactions in detail.

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    Law of Equivalence

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