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Law of Equivalence - Practice Questions & MCQ
Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main
Quick Facts
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23 Questions around this concept.
Solve by difficulty
The volume of 0.02 M aqueous HBr required to neutralize 10.0 mL of 0.01 M aqueous is (Assume complete neutralization)
Calculate the normality of NaOH when 2g is present in 800 ml solution.
Concepts Covered - 1
Law of Equivalence
Laws of Equivalence
According to the law of equivalence, for each and every reactant and product,
Equivalents of each reactant reacted = Equivalents of each product formed.
Example,
Suppose the reaction is taking place as follows:
According to the law of equivalence,
Equivalents of P reacted = Equivalents of Q reacted = Equivalents of R produced = Equivalents of S produced
Equivalents of any substance = (Weight of substance (in g)) / (Equivalent weight)
= Normality (N) x Volume (V) (In litre)
Normality (N) = n-Factor x Molarity (M)
Law of Equivalence finds great importance in Acid base Neutralisation Reactions as well as Redox Titrations.
Here we shall be mainly covering the Acid Base neutralisation reactions in detail.
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