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Into Function, Bijective function, Equality of function is considered one of the most asked concept.
20 Questions around this concept.
Let be a function defined as
where
Show that is invertible and its inverse is?
Let
Statement - 1: The set
Statement - 2: is a bijection.
Statement - 1 (Assertion) and Statement - 2 (Reason).
Which of the following is the mapping for into function?
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Find the no. of bijective functions from $X$ to $Y$, where $n(X)=5=n(Y)$.
Which of the following is a bijective function for $f: \mathbb R\rightarrow \mathbb R$ ?
Which of the following is an Into function for $f: (-\infty, \infty)\rightarrow [0,\infty)$
Into Function:
A function $f: X \rightarrow Y$ is said to be an into function if there exists an element in $Y$ having no preimage in A .
In other words, if $\mathrm{f}: \mathrm{X} \rightarrow \mathrm{Y}$ is not onto mapping then it is an into mapping.
Eg
As the element y2 in codomain does not have a pre-image in domain, so it is into function
Note: If a function is not onto, then it is into and
If a function is not into, then it is onto.
Bijective Function
A function $f: X \rightarrow Y$ is said to be bijective, if $f$ is both one-one and onto (meaning it is both injective and surjective)
Consider, $X_1=\{1,2,3\}$ and $X_2=\{x, y, z\}$
Eg
$\mathrm{f}: \mathrm{x}_1 \rightarrow \mathrm{x}_2$
The number of bijective function:
If $f(x)$ is bijective, and the function is from a finite set $A$ to a finite set $B$, then
$
n(A)=n(B)=m(\text { Say })
$
And, the number of Bijective functions $=\mathrm{m}$ !
Equal Functions
The two functions $f$ and $g$ are said to be equal if
$\operatorname{Domain}(\mathrm{f})=$ Domain(g)
Co-domain(f) = Co-domain(g), and
$f(x)=g(x)$ for all $x$ belonging to domain
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