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Intersection of Set, Properties of Intersection - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Intersection of Set, Properties of Intersection is considered one of the most asked concept.

  • 27 Questions around this concept.

Solve by difficulty

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If A=\left \{ a,c,d,h, i,f,m \right \} and B=\left \{ a,e,d,g,l,j,m \right \}.  Find A\cap B.

In a group of 100 persons 75 speak English and 40 speak Hindi. Each person speaks at least one of the two
languages. If the number of persons, who speak only English is \alpha and the number of persons who speak only
Hindi is \beta, then the eccentricity of the ellipse \mathrm{25\left (\beta ^{2}x^{2}+\alpha ^{2}+y^{2} \right )=\alpha ^{2}\beta ^{2}} is:

An organization awarded 48 medals in event ‘A’, 25 in event ‘B’ and 18 in event ‘C’. If these medals went to total 60 men and only five men got medals in all the three events, then, how many received medals in exactly two of three events ?

Concepts Covered - 1

Intersection of Set, Properties of Intersection

The intersection of sets A and B is the set of all elements which are common to both A and B. The symbol ‘∩ ‘is used to denote the intersection.

 Symbolically, we write A ∩ B = {x: x ∈ A and x ∈ B}

For example, let A = { 2, 4, 6, 8 } and B = { 2, 3, 5, 8 }, then A ∩ B = { 2, 8 }

 

If A and B are two sets such that A ∩ B = φ, then A and B are called disjoint sets.

For example, let A = { 2, 4, 6, 8 } and B = { 1, 3, 5, 7 }. Then A and B are disjoint sets because there are no elements which are common to A and B.

Properties of intersection

  • A \cap B = B \cap A (Commutative law).

  • ( A \cap B ) \cap C = A \cap ( B \cap C ) (Associative law).

  •  A \cap \phi = \phi

  • \cap U = A (Law of \phi and U).

  • A \cap A = A (Idempotent law)

  • If A is subset of B, then A \cap B = A

 

Distributive laws

1.  A \cap ( B \cup C ) = ( A \cap B ) \cup ( A \cap C )  i. e., \cap distributes over \cup

This can be seen easily from the following Venn diagrams

LHS:

    

RHS:

           

 

2. A ∪ (B ∩ C) = (A ∪ B) ∩ (A ∪ C) 

This can be seen easily from the following Venn diagrams

LHS:

         

 

RHS:

           

 

 

 

 

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Intersection of Set, Properties of Intersection

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