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    Intersection of Set, Properties of Intersection - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Intersection of Set, Properties of Intersection is considered one of the most asked concept.

    • 47 Questions around this concept.

    Solve by difficulty

    Which of the following Venn Diagram shows $A\cap B\cap C \,'$  ?

    Which of the following is the correct representation of the set $A \cap B$?

    $(-3,4) \cap[0,5] \cap(5,7]$ equals

    $
    \phi \cap A=?
    $
    Where $\phi$ is a null set.

    If $A=\{x: x \in N$ and $x<5\}$ then $A \cap A=B$ where $\mathrm{B}=$

    Let A = {1,2,3} , B = {3,6} and C = {4,5,6,7} Then $A \cup (B\cap C  )   is$

    What is the distributive property?

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    What is the Idempotent Law?

    Which is the associative property of intersection?

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    Which of the following is a distributive property?

    Concepts Covered - 1

    Intersection of Set, Properties of Intersection

    The intersection of sets $A$ and $B$ is the set of all elements which are common to both $A$ and $B$. The symbol ' $\cap$ 'is used to denote the intersection.

    Symbolically, we write $A \cap B=\{x: x \in A$ and $x \in B\}$
    For example, let $\mathrm{A}=\{2,4,6,8\}$ and $\mathrm{B}=\{2,3,5,8\}$, then $\mathrm{A} \cap \mathrm{B}=\{2,8\}$

    If $A$ and $B$ are two sets such that $A \cap B=\varphi$, then $A$ and $B$ are called disjoint sets.
    For example, let $A=\{2,4,6,8\}$ and $B=\{1,3,5,7\}$. Then $A$ and $B$ are disjoint sets because there are no elements which are common to A and B .

    Properties of intersection
    $\mathrm{A} \cap \mathrm{B}=\mathrm{B} \cap \mathrm{A}$ (Commutative law).
    $(A \cap B) \cap C=A \cap(B \cap C)$ (Associative law).
    $\mathrm{A} \cap \phi=\phi$,
    $\mathrm{A} \cap \mathrm{U}=\mathrm{A}$ (Law of $\phi$ and U$)$.
    $\mathrm{A} \cap \mathrm{A}=\mathrm{A}$ (Idempotent law)
    If $A$ is subset of $B$, then $A \cap B=A$

    Distributive laws

    1. $A \cap(B \cup C)=(A \cap B) \cup(A \cap C)$ i. e., $\cap$ distributes over $\cup$

    This can be seen easily from the following Venn diagrams

    LHS:

        

    RHS:

               

    2. $A \cup(B \cap C)=(A \cup B) \cap(A \cup C)$

    This can be seen easily from the following Venn diagrams

    LHS:

             

    RHS:

               

     

     

     

     

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    Intersection of Set, Properties of Intersection

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