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Cardinal number of some sets is considered one the most difficult concept.
25 Questions around this concept.
Given $\mathrm{n}(\mathrm{U})=150, \mathrm{n}(\mathrm{A})=60, \mathrm{n}(\mathrm{B})=50$ and $n(A \cap B)=0$. Find the shaded portion.
For disjoint sets $A$ \& $B, n(A U B)=10$ and $n(A)=5$ then $n(B)=$ ?
If a class has 50 students, 7 opted for maths and 45 for biology. How many students have opted for both?
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If P and Q are two sets such that P has 21 elements, Q has 32 elements, and $P \cap Q$ has 11 elements, then number of elements $P \cup Q{\text { has }}$
In a city 20% of the population travels by car, 50% travels by bus and 10% travels by both car and bus. Then person travelling by car or bus is
The set (A ∩ B′)′ ∪ (B ∩ C) is equal to
The number of distinct elements in a finite set A is called the Cardinal number of set A and it is denoted by $\mathrm{n}(\mathrm{A})$.
For example, if set $A=\{1,3,7,11,13\}$ then $n(A)=5$
Given, any two finite sets A and B, then the Number of Elements in the union of sets A \& B is given by $n(A \cup B)=n(A)+n(B)-n(A \cap B)$
If $(A \cap B)=\varphi$, then $n(A \cup B)=n(A)+n(B)$
Given A, B, and C are any finite sets, then the Number of Elements in the union of sets A, B \& C is given by
$\mathrm{n}(\mathrm{A} \cup \mathrm{B} \cup \mathrm{C})=\mathrm{n}(\mathrm{A})+\mathrm{n}(\mathrm{B})+\mathrm{n}(\mathrm{C})-\mathrm{n}(\mathrm{A} \cap \mathrm{B})-\mathrm{n}(\mathrm{B} \cap \mathrm{C})-\mathrm{n}(\mathrm{A} \cap \mathrm{C})+\mathrm{n}(\mathrm{A} \cap \mathrm{B} \cap \mathrm{C})$
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