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Terms associated with SHM is considered one of the most asked concept.
23 Questions around this concept.
The correct figure that shows, schematically , the wave pattern produced by the superposition of two waves of frequencies 9 Hz and 11 Hz, is:
Two simple harmonic motions are represented by the equations
The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 at t=0 is:
A point mass oscillates along the x-axis according to law . If the acceleration of the particle is written as then
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The speed of the wave in a medium is 760 m/s. If 3600 waves are passing through a point, in the medium in 2 minutes, then its wavelength is
Amplitude:-
We know that displacement of a particle in SHM is given by:
$x=A \operatorname{Sin}(\omega t+\phi)$
The quantity A is called the amplitude of the motion. It is a positive constant which represents the magnitude of the maximum displacement of the particle from mean position in either direction.
Time period:-
$
x=\operatorname{ASin}(\omega t+\phi)
$
If a motion is periodic with a period $T$, then the displacement $x(t)$ must return to its initial value after one period of the motion; that is, $x(t)$ must be equal to $x(t+T)$ for all $t$ and velocity $v(t)$ must also return to its initial value, i.e., $v(t)$ must be equal to $v(t+T)$. So,
$
\begin{aligned}
& x(t)=x(t+T) \\
\Rightarrow & A \operatorname{Sin}(\omega t+\phi)=A \operatorname{Sin}[\omega[t+T]+\phi] \\
\Rightarrow & \operatorname{Sin}(\omega t+\phi)=\operatorname{Sin}[\omega[t+T]+\phi]
\end{aligned}
$
And
$
\begin{aligned}
& v(t)=v(t+T) \\
\Rightarrow & A \omega \operatorname{Cos}(\omega t+\phi)=A \omega \operatorname{Cos}[\omega[t+T]+\phi] \\
\Rightarrow & \operatorname{Cos}(\omega t+\phi)=\operatorname{Cos}[\omega[t+T]+\phi]
\end{aligned}
$
As we know both Sine and Cosine function repeats itself when their argument increases by $2 \pi$,i.e.,
$
\begin{aligned}
& \omega t+\phi+2 \pi=\omega(t+T)+\phi \\
& \Rightarrow 2 \pi=T \omega \\
& \Rightarrow T=\frac{2 \pi}{\omega}=2 \pi \sqrt{\frac{m}{k}}
\end{aligned}
$
$
\text { where } k=\text { force or spring constant and } m=\text { mass }
$
- Time period can also be written as:-
$
T=\frac{2 \pi}{\omega}=2 \pi \sqrt{\frac{m}{k}}=2 \pi \sqrt{\frac{m}{\frac{\text { Force }}{\text { displacement }}}}=2 \pi \sqrt{\frac{m \times \text { displacement }}{m \times \text { acceleration }}}
$
$
\Rightarrow T=2 \pi \sqrt{\frac{\text { displacement }}{\text { acceleration }}}
$
3. Frequency:-
The reciprocal of T gives the number of repetitions that occur per unit time. This quantity is called the frequency of the periodic motion.
- It is denoted by f .
$
\begin{aligned}
& f=\frac{1}{T}=\frac{\omega}{2 \pi}=\frac{1}{2 \pi} \sqrt{\frac{k}{m}} \\
& \Rightarrow \omega=2 \pi f ; \text { where } \omega \text { is angular frequency }
\end{aligned}
$
- The unit of frequency is $s^{-1}$ or $\operatorname{Hertz}(\mathrm{Hz})$.
4. Phase:-
. The quantity $(\omega t+\Delta \phi)$ is called the phase.
- It determines the status of the particle in simple harmonic motion.
- If the phase is zero at a certain instant, then:
$
x=A \operatorname{Sin}(\omega t+\phi)=0 \text { and } v=A \omega \operatorname{Cos}(\omega t+\phi)=A \omega
$
which means that the particle is crossing the mean position and is going towards the positive direction.
Fig:- Status of the particle at different phases
5. Phase constant:-
- The constant $\phi$ is called the phase constant (or phase angle).
- The value of $\phi$ depends on the displacement and velocity of the particle at $t=0$ or we can say the phase constant signifies the initial conditions.
- Any instant can be chosen as $\mathrm{t}=0$ and hence the phase constant can be chosen arbitrarily.
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