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Terms associated with SHM is considered one of the most asked concept.
26 Questions around this concept.
The correct figure that shows, schematically, the wave pattern produced by the superposition of two waves of frequencies 9 Hz and 11 Hz, is:
Two simple harmonic motions are represented by the equations
The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 at t=0 is:
A point mass oscillates along the x-axis according to law . If the acceleration of the particle is written as then
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The speed of the wave in a medium is 760 m/s. If 3600 waves are passing through a point, in the medium in 2 minutes, then its wavelength is
Amplitude:-
We know that displacement of a particle in SHM is given by:
$x=A \operatorname{Sin}(\omega t+\phi)$
The quantity A is called the amplitude of the motion. It is a positive constant which represents the magnitude of the maximum displacement of the particle from mean position in either direction.
Time period:-
$
x=\operatorname{ASin}(\omega t+\phi)
$
If a motion is periodic with a period $T$, then the displacement $x(t)$ must return to its initial value after one period of the motion; that is, $x(t)$ must be equal to $x(t+T)$ for all $t$ and velocity $v(t)$ must also return to its initial value, i.e., $v(t)$ must be equal to $v(t+T)$. So,
$
\begin{aligned}
& x(t)=x(t+T) \\
\Rightarrow & A \operatorname{Sin}(\omega t+\phi)=A \operatorname{Sin}[\omega[t+T]+\phi] \\
\Rightarrow & \operatorname{Sin}(\omega t+\phi)=\operatorname{Sin}[\omega[t+T]+\phi]
\end{aligned}
$
And
$
\begin{aligned}
& v(t)=v(t+T) \\
\Rightarrow & A \omega \operatorname{Cos}(\omega t+\phi)=A \omega \operatorname{Cos}[\omega[t+T]+\phi] \\
\Rightarrow & \operatorname{Cos}(\omega t+\phi)=\operatorname{Cos}[\omega[t+T]+\phi]
\end{aligned}
$
As we know both Sine and Cosine function repeats itself when their argument increases by $2 \pi$,i.e.,
$
\begin{aligned}
& \omega t+\phi+2 \pi=\omega(t+T)+\phi \\
& \Rightarrow 2 \pi=T \omega \\
& \Rightarrow T=\frac{2 \pi}{\omega}=2 \pi \sqrt{\frac{m}{k}}
\end{aligned}
$
$
\text { where } k=\text { force or spring constant and } m=\text { mass }
$
- Time period can also be written as:-
$
T=\frac{2 \pi}{\omega}=2 \pi \sqrt{\frac{m}{k}}=2 \pi \sqrt{\frac{m}{\frac{\text { Force }}{\text { displacement }}}}=2 \pi \sqrt{\frac{m \times \text { displacement }}{m \times \text { acceleration }}}
$
$
\Rightarrow T=2 \pi \sqrt{\frac{\text { displacement }}{\text { acceleration }}}
$
3. Frequency:-
The reciprocal of T gives the number of repetitions that occur per unit time. This quantity is called the frequency of the periodic motion.
- It is denoted by f .
$
\begin{aligned}
& f=\frac{1}{T}=\frac{\omega}{2 \pi}=\frac{1}{2 \pi} \sqrt{\frac{k}{m}} \\
& \Rightarrow \omega=2 \pi f ; \text { where } \omega \text { is angular frequency }
\end{aligned}
$
- The unit of frequency is $s^{-1}$ or $\operatorname{Hertz}(\mathrm{Hz})$.
4. Phase:-
. The quantity $(\omega t+\Delta \phi)$ is called the phase.
- It determines the status of the particle in simple harmonic motion.
- If the phase is zero at a certain instant, then:
$
x=A \operatorname{Sin}(\omega t+\phi)=0 \text { and } v=A \omega \operatorname{Cos}(\omega t+\phi)=A \omega
$
which means that the particle is crossing the mean position and is going towards the positive direction.
Fig:- Status of the particle at different phases
5. Phase constant:-
- The constant $\phi$ is called the phase constant (or phase angle).
- The value of $\phi$ depends on the displacement and velocity of the particle at $t=0$ or we can say the phase constant signifies the initial conditions.
- Any instant can be chosen as $\mathrm{t}=0$ and hence the phase constant can be chosen arbitrarily.
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