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Composition of two SHM- part 2 is considered one of the most asked concept.
30 Questions around this concept.
The displacement equations of two interfering waves are given by , respectively. The amplitude of the resultant wave is ____.
When the waves and are superposed, then resultant amplitude will be:
Assertion: A closed pipe and an open pipe cannot be in resonance with the same tuning fork, if the length of the closed pipe is integral multiple of the length of the open pipe.
Reason: An odd number is not divisible by even numbers.
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Composition of two SHM:
If a particle is acted upon by two forces such that each force can produce SHM, then the resultant motion of the particle is a combination of SHM.
Composition of two SHM in the same direction
Let a force $F_1$ produces an SHM of amplitude $A_1$ whose equation is given by
$
x_1=A_1 \sin \omega t
$
Let another force $F_2$ produce an SHM of amplitude $A_2$ whose equation is given by
$
x_2=A \sin (\omega t+\phi)
$
Now if force $F_1$ and $F_2$ is acted on the particle in the same direction then the resultant amplitude of the combination of SHM's is given by
$
A=\sqrt{A_1^2+A_2^2+2 A_1 A_2 \cdot \cos \phi}
$
$A_1$ and $A_2$ are the amplitude of two SHM's. $\phi$ is phase difference.
Note: Here the frequency of each SHM's are the same
And the resulting phase is given by
$
\phi^{\prime}=\tan ^{-1}\left(\frac{A_2 \sin \phi}{A_1+A_2 \cos \phi}\right)
$
Composition of SHM in perpendicular direction:
Let a force $\mathrm{F}_1$ on a particle produces an SHM given by
$
x=A \sin \omega t
$
and a force $\mathrm{F}_2$ alone produces an SHM given by
$
x=A \sin (\omega t+\phi)
$
- Both the force $F_1$ and $F_2$ acting perpendicular on the particle will produce an SHM whose resultant is given by:
$
\frac{x^2}{A_1^2}+\frac{y_2^2}{A_2^2}-\frac{2 x y \cos \phi}{A_1 A_2}=\sin ^2 \phi
$
The above equation is the general equation of an ellipse. That is two forces acting perpendicular on a particle execute SHM along an elliptical path.
- When $\phi=0$ resultant equation is given by
$
y=\frac{A_2}{A_1} \cdot x
$
It is a straight line with slope
$\frac{A_2}{A_1}$ represented by the below figure
- When $\phi=\pi$ resultant equation
$
y=\frac{-A_2}{A_1} \cdot x
$
which is represented by below straight line with slope $\frac{-A_2}{A_1}$
- When $\phi=\frac{\pi}{2}$ resultant equation
$
\frac{x^2}{A_1^2}+\frac{y^2}{A_2^2}=1
$
It represents a normal ellipse
- if
$A_1=A_2$ and $\phi=\frac{\pi}{2}$ then it represents a circle
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