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Simple harmonic as projection of circular motion is considered one of the most asked concept.
8 Questions around this concept.
Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to A and T, respectively. At time t = 0 one particle has displacement A while the other one has displacement and they are moving towards each other. If they cross each other at time t, then t is :
For particle revolving round the centre with radius of circular path and angular velocity , as shown in below figure, the projection of on the -axis at time is
Simple harmonic can be represented as a projection of circular motion.
If P moves uniformly on a circle as shown in the below figure, then its projection P′ on a diameter of the circle executes SHM.
As the particle P moves on the circle, The position of P′ on the x-axis is given by
x(t) = A cos (ωt + φ)
This is the equation of SHM on the x-axis with amplitude A and angular frequency as
Where A is the radius of the circle
and is the angle that the radius OP makes with the x-axis at t=0
Similarly, The position of P′ on the y-axis is given by
y(t)= A sin (ωt + φ)
This also an SHM of the same amplitude as that of the projection on the x-axis, but differing by a phase of π/2.
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