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    JEE Main High Scoring Topics 2026 - Subject-Wise List

    Entropy - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Entropy is considered one of the most asked concept.

    • 21 Questions around this concept.

    Solve by difficulty

    Which of the following is incorrect regarding the first law of thermodynamics?

    The temperature­- entropy diagram of a reversible engine cycle is given in the figure. Its efficiency is

    choose the correct equation for entropy change for ideal gas in terms of T& V

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    Concepts Covered - 1

    Entropy

    Entropy- Entropy is a measure of the disorder of the molecular motion of a system. I.e Greater is the disorder, greater is the entropy.

    The change in entropy is given as

    $
    d S=\frac{\text { Heat absorbed by system }}{\text { Absolute temperature }} \text { or } d S=\frac{d Q}{T}
    $


    The relation

    $
    d S=\frac{d Q}{T}
    $

    1. Entropy for solid and liquid-
    i. When heat is given to a substance to change its state at a constant temperature.

    Then change in entropy is given as

    $
    d S=\frac{d Q}{T}= \pm \frac{m L}{T}
    $

    where positive sign refers to heat absorption and negative sign to heat evolution.
    And $L=$ Latent Heat and T is in kelvin.
    ii. When heat is given to a substance to raises its temperature from $T_1$ to $T_2$

    Then change in entropy is given as

    $
    d S=\int \frac{d Q}{T}=\int_{T_1}^{T_2} m c \frac{d T}{T}=m c \log _e\left(\frac{T_2}{T_1}\right)=2.303 * \mathrm{mc}^{-\log _{10}}\left(\frac{T_2}{T_1}\right)
    $

    where $\mathrm{c}=$ specific heat capacity
    2. Entropy for an ideal gas -

    For $n$ mole of an ideal gas, the equation is given as $P V=n R T$
    I.Entropy change for ideal gas in terms of T \& V

    From the first law of thermodynamics, we know that $d Q=d W+d U$

    $
    \text { and } \Delta S=\int \frac{d Q}{T}=\int \frac{n C_V d T+P d V}{T}
    $
     

    using $\mathrm{PV}=\mathrm{nRT}$

    $
    \begin{aligned}
    & \Delta S=\int \frac{n C_V d T+\frac{n R T}{V} d V}{T}=n C_V \int_{T_1}^{T_2} \frac{d T}{T}+n R \int_{V_1}^{V_2} \frac{d V}{V} \\
    & \Delta S=n C_V \ln \left(\frac{T_2}{T_1}\right)+n R \ln \left(\frac{V_2}{V_1}\right)
    \end{aligned}
    $

    II.Entropy change for an ideal gas in terms of T \& P

    $
    \Delta S=n C_P \ln \left(\frac{T_2}{T_1}\right)-n R \ln \left(\frac{P_2}{P_1}\right)
    $

    III.Entropy change for an ideal gas in terms of $\mathrm{P} \& \mathrm{~V}$

    $
    \Delta S=n C_V \ln \left(\frac{P_2}{P_1}\right)+n C_P \ln \left(\frac{V_2}{V_1}\right)
    $
     

     

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