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Composition of function, Condition for Composite Function, Property of Composite Function is considered one of the most asked concept.
41 Questions around this concept.
Let $$f(x)=2^{10} \cdot x+1 \text { and } g(x)=3^{10} \cdot x-1 \text {. If }(f \circ g)(x)=x$$, then x is equal to:
If $\mathrm{f}(\mathrm{x})=\frac{4 \mathrm{x}+3}{6 \mathrm{x}-4}, \mathrm{x} \neq \frac{2}{3}$ and (fof) (x) $\mathrm{g}(\mathrm{x})$, where $\mathrm{g}: \mathbb{R}-\left\{\frac{2}{3}\right\} \rightarrow \mathbb{R}-\left\{\frac{2}{3}\right\}$, then (gogog)(4) is equal to
Let $\mathrm{f}: \mathrm{A} \rightarrow \mathrm{B}$ and $\mathrm{g}: \mathrm{B} \rightarrow \mathrm{C}$ be two functions. Then the composition of f and g is denoted by gof and defined as the function gof : $\mathrm{A} \rightarrow \mathrm{C}$ given by $\operatorname{gof}(x)=g(f(x))$
Properties of composition:
In general fog $\neq$ gof (Not commutative)
$\mathrm{fo}(\mathrm{goh})=(\mathrm{fog})$ oh $\quad$ (Associative $)$
If $f$ and $g$ are bijections then fog and gof are also bijections
The composition of any function with the identity function is the function itself. If $f: A \rightarrow B$, then $f o I_A=I_B o f=f$
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