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9 Questions around this concept.
The total number of primary, secondary and tertiary amines possible with the molecular formula C3H9N respectively
Compound with molecular formula C3H6O can show :
Consider the substrate given below:
This is allowed to undergo hydrogenation reaction in presence of metals like Ni or Pt as catalyst The difference in the degree of unsaturation of the reactant and product is
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Adsorption
The phenomenon of the deposition of particles on the surface of the adsorbent is called adsorption.
For example, the rate of adsorption among the following molecules is higher for cyclopentene.
Cyclopentene Cyclohexene
Since the size of cyclopentene is smaller than cyclohexene, thus the rate of adsorption is higher for cyclopentene than cyclohexene.
Occlusion
The adsorption of hydrogen on the surface of the noble metals is known as occlusion. These noble metals can be Platinum or Palladium.
Degree of Unsaturation
It is the calculation to analyse the total number of double bonds and rings in the organic compound. It is also known as index of hydrogen deficiency or unsaturation index.
Where, C is the number of Carbon atoms, H is the number of Hydrogen atoms, N is the number of Nitrogen atoms and X is the number of Halogen atoms. It is to be noted that the Oxygen atoms have no bearing on the degree of unsaturation
Now for the compound C10H6N4 we have, x = 10, y = 6 and z = 4
Thus, degree of unsaturation = (10 + 1) - (6 + 0 - 4)/2
Degree of unsaturation = 10
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