The Parallel Plate Capacitor - Practice Questions & MCQ

. As shown in the figure, a very thin sheet of aluminium is placed in between the plates of the condenser. Then the capacity

Between the plates of a parallel plate condenser, a plate of thickness $t_1$ and dielectric constant $k_1$ is placed. In the rest of the space, there is another plate of thickness $t_2$ and dielectric constant $k_2$. The potential difference across the condenser will be

Plate separation of a $15 \mu\mathrm{~F}$ capacitor is 2 mm. A dielectric slab $(K=2)$ of thickness 1 mm is inserted between the plates. Then new capacitance is given by

A sheet of aluminium foil of negligible thickness is introduced between the plates of a capacitor. The capacitance of the capacitor

When a dielectric material is introduced between the plates of a charge condenser, then electric field between the plates

Two identical thin metal plates has charge $\mathrm{q}_1$ and $\mathrm{q}_2$ respectively such that $\mathrm{q}_1>\mathrm{q}_2$. The plates were brought close to each other to form a parallel plate capacitor of capacitance C . The potential difference between them is :

A capacitor of capacitance C is charged to a potential V. The flux of the electric field through a closed surface enclosing the positive plate of the capacitor is :

The capacity of parallel plate capacitor increases with the

Force of attraction between the plate of a parallel olate capacitor is:

Consider a parallel plate capacitor of 8μF (micro-farad) with air filled in the gap between the plates. Now half of the space between the plates is filled with a dielectric of dielectric constant 4, as shown in the figure. The capacity of the capacitor changes to