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Coulomb's Law is considered one the most difficult concept.
69 Questions around this concept.
Two identical charged spheres suspended from a common point by two massless strings of length are initially a distance apart because of their mutual repulsion. The charge begins to leak from both spheres at a constant rate. As a result, the charges approach each other with a velocity . Then the relation between v and x is:
A charge Q is placed at each of the opposite corners of a square. A charge q is placed at each of the other two corners. If the net electrical force on Q is zero, then the Q/q equals
Two spherical conductors B and C having equal radii and carrying equal charges in them repel each other with a force F when kept apart at some distance.A third spherical conductor having same radius as that of B but uncharged is brought in contact with B then brought in contact with C and finally removed away from both, The new force of repulsion between B and C is :
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Two charges equal in magnitude and opposite in polarity are placed at a certain distance apart and force acting between them is F. If 75% charge of one is transferred to another, then the force between the charges becomes
Two charges and are placed in vacuum at a distance and the force acting between them is . If a medium of dielectric constant 4 is introduced around them, the force now will be:
A pendulum bob of mass and carrying a charge is at rest in a horizontal uniform electric field of 20000 V/m. The tension in the thread of the pendulum is ( g = 10 m/s2) :
In the given figure two tiny conducting balls of identical mass m and identical charge hang from non-conducting threads of equal length L. Assume that is so small that, then for equilibrium is equal to
Coulomb's Law: The force of attraction or repulsion between two charges is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them.
$
\begin{aligned}
& F \propto \frac{Q_1 Q_2}{r^2} \\
& F=\frac{K Q_1 Q_2}{r^2}
\end{aligned}
$
$\mathrm{K}=$ Proportionality Constant
$Q_1$ and $Q_2$ are two Point charges
In SI unit value of K is
$
K=\frac{1}{4 \pi \varepsilon_0}
$
Where,
$
\left(\varepsilon_0\right)=8.85 \times 10^{-12} \frac{C^2}{N-m^2} \text { known as absolute permittivity of air or free }
$
space
The vector form of Coulomb's Law:
Consider two charges $q_1$ and $q_2$ separated by a distance r. Let the position vectors of $q_1$ be $r_1$ and that of $q_2$ be $r_2$. Then the force due to $q_2$ on $q_1$ as shown in figure $F_{12}$ is directed along the unit vector $r_{12}$ and
$
\begin{aligned}
& F_{12}=\frac{K q_1 q_2}{r^2} \hat{r}_{12} \\
& \text { here, } \hat{r}_{12}=\frac{\vec{r}_1-\vec{r}_2}{\left|r_1-r_2\right|}=\frac{\vec{r}_{12}}{r} \\
& F_{12}=\frac{K q_1 \cdot q_2}{r^3} \vec{r}_{12}
\end{aligned}
$
Force when dielectric inserted between the charges:
When a dielectric of dielectric constant $k$ is completely filled between the charges then force
$
F_{\text {med }}=\frac{q_1 q_2}{4 \pi \varepsilon_0 k r^2}=\frac{q_1 q_2}{4 \pi \varepsilon_0 \epsilon_r r^2}
$
$\epsilon_r$ is relative permittivity / dielectric constant of the medium. The dielectric constant is the ratio of the permittivity of a substance to the permittivity of free space. (dielectric will be explained later in detail in this chapter)
If the dielectric of thickness d is partially filled between the charges $Q_1$ and $Q_2$ then
$F=\frac{Q_1 Q_2}{4 \pi \epsilon_0(r-d+\sqrt{k} d)^2}$
Principle of Superposition:
It states that the total force acting on a given charge due to a number of charges is the Vector sum of the individual forces acting on that charge due to all the charges.
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