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Coulomb's Law - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Coulomb's Law is considered one the most difficult concept.

  • 76 Questions around this concept.

Solve by difficulty

Two identical charged spheres suspended from a common point by two massless strings of length l are initially a distance d(d< < l) apart because of their mutual repulsion. The charge begins to leak from both spheres at a constant rate. As a result, the charges approach each other with a velocity \upsilon. Then the relation between v and x is:

With the rise in temperature, the dielectric constant $K$ of a liquid

A force $F$ acts between sodium and chlorine ions of salt (sodium chloride) when put 1 cm apart in air. The permittivity of air and dielectric constant of water are $\varepsilon_0$ and $K$ respectively. When a piece of salt is put in water electrical force acting between sodium and chlorine ions 1 cm apart is

A charge Q is placed at each of the opposite corners of a square. A charge q is placed at each of the other two corners. If the net electrical force on Q is zero, then the Q/q equals

Two spherical conductors B  and C   having equal radii and carrying equal charges in them repel each other with a force  F   when kept apart at some distance.A   third spherical conductor having same radius as that of  B   but uncharged is brought in contact with  B   then brought in contact with   C  and  finally removed away from both, The new force of repulsion between  B  and  C   is  :

Two charges equal in magnitude and opposite in polarity are placed at a certain distance apart and force acting between them is F. If 75% charge of one is transferred to another, then the force between the charges becomes

Two charges q_{1} and q_{2} are placed in vacuum at a distance d  and the force acting between them is F. If a medium of dielectric constant 4 is introduced around them, the force now will be:

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A pendulum bob of mass and carrying a charge is at rest in a horizontal uniform electric field of 20000 V/m. The tension in the thread of the pendulum is ( g = 10 m/s2) :

In the given figure two tiny conducting balls of identical mass m and identical charge $q$ hang from non-conducting threads of equal length L . Assume that $\tan \theta \approx \sin \theta$ is so small that, then for equilibrium $x$ is equal to

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The magnitude of electric force between two charged particle depends on:

Concepts Covered - 1

Coulomb's Law

Coulomb's Law: The force of attraction or repulsion between two charges is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them.

                                 

$
\begin{aligned}
& F \propto \frac{Q_1 Q_2}{r^2} \\
& F=\frac{K Q_1 Q_2}{r^2}
\end{aligned}
$

$\mathrm{K}=$ Proportionality Constant
$Q_1$ and $Q_2$ are two Point charges
In SI unit value of K is

$
K=\frac{1}{4 \pi \varepsilon_0}
$


Where,

$
\left(\varepsilon_0\right)=8.85 \times 10^{-12} \frac{C^2}{N-m^2} \text { known as absolute permittivity of air or free }
$

space


 

The vector form of Coulomb's Law: 

                                                       

Consider two charges $q_1$ and $q_2$ separated by a distance r. Let the position vectors of $q_1$ be $r_1$ and that of $q_2$ be $r_2$. Then the force due to $q_2$ on $q_1$ as shown in figure $F_{12}$ is directed along the unit vector $r_{12}$ and

$
\begin{aligned}
& F_{12}=\frac{K q_1 q_2}{r^2} \hat{r}_{12} \\
& \text { here, } \hat{r}_{12}=\frac{\vec{r}_1-\vec{r}_2}{\left|r_1-r_2\right|}=\frac{\vec{r}_{12}}{r} \\
& F_{12}=\frac{K q_1 \cdot q_2}{r^3} \vec{r}_{12}
\end{aligned}
$


Force when dielectric inserted between the charges:
When a dielectric of dielectric constant $k$ is completely filled between the charges then force

$
F_{\text {med }}=\frac{q_1 q_2}{4 \pi \varepsilon_0 k r^2}=\frac{q_1 q_2}{4 \pi \varepsilon_0 \epsilon_r r^2}
$

$\epsilon_r$ is relative permittivity / dielectric constant of the medium. The dielectric constant is the ratio of the permittivity of a substance to the permittivity of free space. (dielectric will be explained later in detail in this chapter)

If the dielectric of thickness d is partially filled between the charges $Q_1$ and $Q_2$ then

                                                                                 

                                                                            $F=\frac{Q_1 Q_2}{4 \pi \epsilon_0(r-d+\sqrt{k} d)^2}$

 

Principle of Superposition:

It states that the total force acting on a given charge due to a number of charges is the Vector sum of the individual forces acting on that charge due to all the charges.

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Coulomb's Law

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