EASYVIT - VITEEE 2025
National level exam conducted by VIT University, Vellore | Ranked #11 by NIRF for Engg. | NAAC A++ Accredited | Last Date to Apply: 31st March | NO Further Extensions!
Motion of charged particle in uniform electric field - Practice Questions & MCQ
Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main
Quick Facts
-
48 Questions around this concept.
Solve by difficulty
A positively charged particle moving along the x-axis with a certain velocity enters a uniform electric field directed along the positive y-axis. Its
An electron moving with the speed of m/s is shot parallel to the electric field of intensity
. The field is responsible for the retardation of the motion of electrons. Now evaluate the distance travelled by the electron before coming to rest for an instant (mass of
charge
)
A mass of 1g carrying charge q falls through a potential difference V. The kinetic energy acquired by it is E. When a mass of 2g carrying the charge q falls through a potential difference V. What will be the kinetic energy acquired by it?
JEE Main 2025: Admit Card Link | Study Plan | Official Question Paper (Session 1)
JEE Main 2025: Sample Papers | Mock Tests | PYQs | High Scoring Topics | College Predictor
New: Meet Careers360 experts in your city and get guidance on shortlisting colleges
Apply to TOP B.Tech /BE Entrance exams: VITEEE | MET | AEEE | BITSAT
Direction : In the following question, a statement of Assertion ( A ) is followed by a statement of reason (R). Mark the correct choice as
Assertion : If a charge enters in electric field then it must move in the direction of electric field .
Reason : Force on the charge is always in the opposite direction of electric field .
A charged particle of mass m and charge +Q is balanced in the air due to an electric field direction in a vertically upward direction the value of the magnitude of the electric field is:
A particle having charge Q and mass m rests at A and in time t reaches point B. If the potential difference between point A and B is $\Delta V$ then velocity at point B depends upon $\Delta V$ as:
If the motion of the charged particle is accelerated then it produces-
Concepts Covered - 1
Motion of charged particle in uniform electric field
Motion of charged particle in uniform electric field -
Whenever a charged placed in an electric field, it will experience an electric force. Ther is an assumption that this whole system is placed in an gravity free space. For this condition, electrical force is the only force acting on the particle. This net forcce will cause the particle to accelerate according to Newton's second law of motion. So we can write -
$
\vec{F}_e=q \vec{E}=m \vec{a}
$
Acceleration will be constant if the Electric field will be uniform and
$
\vec{a}=\frac{q \vec{E}}{m}
$
The dierection of acceleration or motion of charged particle depends on its nature. If the charged particle is of positive nature then it will move or accelerate in the direction of electric field. But in case of negative charged particle its motion or acceleration is in opposite direction of electric field. Here we can use the kinematic equation of motion since the acceleration is constant.
Study it with Videos
Motion of charged particle in uniform electric field"Stay in the loop. Receive exam news, study resources, and expert advice!"
Get Answer to all your questions
JEE Main Articles
Back to top