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Onto Function or Surjective is considered one the most difficult concept.
7 Questions around this concept.
Let A = {x1,x2,x3......,x7} and B = { y1 ,y2 ,y3 } be two sets containing seven and three distinct elements respectively. Then the total number of functions : A
B that are onto, if there exist exactly three elements x in A such that
(x) = y2, is equal to :
A function f : X → Y is said to be onto (or surjective), if every element of Y is the image of some element of X under f, i.e., for every y ∈ Y, there exists an element x in X such that f(x) = y
Hence, Range = co-domain for an onto function
Some examples of onto function
Consider, X = {x1, x2, x3, x4} and Y = {y1, y2, y3}
f : X ⟶ Y
As every element in Y has a pre-image in X, so it is an onto function
Method to show onto or surjective
Find the range of y = f(x) and show that range of f(x) = co-domain of f(x)
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Last Date to Apply : 15th September | Campuses in Agartala, Aizawl, Ajmer, Aurangabad, Calicut, Imphal, Itanagar, Kohima, Gorakhpur, Patna & Srinagar
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