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4 Questions around this concept.
A cycle consisting of one constant pressure, one constant volume, and two isentropic processes is known as
Consider a heat engine as shown in the figure. $Q_1$ And $Q_2$ are heat added to the heat bath $T_1$ and heat is taken from $T_2$ in one cycle of the engine. $W$ is the mechanical work done on the engine.
If $W>0$, then possibilities are:
a) $Q_1>Q_2>0$
b) $Q_2>Q_1>0$
c) $Q_2<Q_1<0$
d) $Q_1<0, Q_2>0$
A heat engine is a device that converts heat into work continuously through a cyclic process.
The essential parts of a heat engine are
1. Source: It is a reservoir of heat at high temperature and infinite thermal capacity. Any amount of heat can be extracted from it.
2. Working substance: Steam, petrol, etc.
3. Sink: It is a reservoir of heat at low temperature and infinite thermal capacity. Any amount of heat can be given to the sink.
As shown in the above figure, The working substance absorbs heat Q1 from the source, does an amount of work W returns the remaining amount of heat (i.e Q2) to the sink and comes back to its original state and there occurs no change in its internal energy.
To obtain work continuously, the same cycle is repeated over and over again.
$$
\text { I.e } \eta=\frac{\text { Work done }}{\text { Heat input }}=\frac{W}{Q_1}
$$
For a cyclic process $\Delta U=0$
so From the first law of thermodynamics, $\therefore \Delta Q=\Delta W \quad$ so $\quad W=Q_1-Q_2$
$$
\eta=\frac{Q_1-Q_2}{Q_1}=1-\frac{Q_2}{Q_1}
$$
Practically efficiency of an engine is always less than 1.
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