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    Freundlich Isotherm - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:35 AM | #JEE Main

    Quick Facts

    • Freundlich Isotherm is considered one the most difficult concept.

    • 30 Questions around this concept.

    Solve by difficulty

    According to Freundlich adsorption isotherm, which of the following is correct ?

    For a linear plot of log(x/m) versus log(p) in a Freundlich adsorption isotherm, which of the following statements is correct?  (k and n are constants)

    For a reversible process at T=300k, the volume of 2 mole of ideal gas is increased from 1 litre to 10 litres, the $\delta H$ for isothermal change is:

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    For adsorption of a gas on a solid, the plot of log $\frac{x}{m}$ Vs log p is linear with slope equal to

    Length of y - axis Intercept can be written as ____________ in logarithmic graph of  isotherm 

    Which of the following curves is in accordance with Freundlich adsorption isotherm?

     

    Concepts Covered - 0

    Freundlich Isotherm

    Freundlich adsorption isotherm:

    Freundlich, in 1909, gave an empirical relationship between the quantity of gas adsorbed by unit mass of solid adsorbent and pressure at a particular temperature. The relationship can be expressed by the following equation:

    \mathrm{\frac{x}{m}= k.p^{1/n}} (n>1)

    where x is the mass of the gas adsorbed on mass m of the adsorbent at pressure P, k and n are constants which depend on the nature of the adsorbent and the gas at a particular temperature.

    The relationship is generally represented in the form of a curve where mass of the gas adsorbed per gram of the adsorbent is plotted against pressure (Fig). These curves indicate that at a fixed pressure, there is a decrease in physical adsorption with increase in temperature. These curves always seem to approach saturation at high pressure.

    Surface Chemistry Image 1

    Logarithmic graph of Freundlich isotherm

    Taking the logarithm of Eq. we get

    \mathrm{log\frac{x}{m}= log\ k+\frac{1}{n}log\ p}

    The validity of the Freundlich isotherm can be verified by plotting log(x/m) on the y-axis (ordinate) and log(p) on the x-axis (abscissa). If it comes to be a straight line, the Freundlich isotherm is valid, otherwise not (Fig.). The slope of the straight line gives the value of  \mathrm{\frac{1}{n}} . The intercept on the y-axis gives the value of log k.

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