End Correction - Practice Questions & MCQ

End correction -

In the organ pipe as we have studied in last concept, when the wave reaches the open end, due to collision particle sactters away from the pipe. Due to this the density reduces outside the pipe and form a rarer medium. 

So, we can say that the wave is not exactly reflected back from the open end of the pipe. So, we can say that the antinodes will form always little away from the open ends. We can see this in the given figure. So the distance above the open end where an antinode is form is called end correction. 

This end corrrection varies with radius of pipe and given as = 

Now taking the end correction into account, the frequency of a closed pipe of length  can be given as - 

                                                                                   (One end open)

For open pipe - 

                                                                                 (Both ends open)

This end corrrection varies with radius of pipe and given as $=e=0.6 \mathrm{r}$
Now taking the end correction into account, the frequency of a closed pipe of length $l$ can be given as -

$
n_o=\frac{\nu}{4(l+e)}
$

(One end open)
For open pipe -

$
n_o=\frac{\nu}{2(l+2 e)}
$

(Both ends open)