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Electrostatic Potential energy is considered one of the most asked concept.
45 Questions around this concept.
In free space, a particle A of charge $1 \mu C$ is held fixed at a point P. Another particle B of the same charge and mass of $4 \mu \mathrm{~kg}$ is kept at a distance of 1 mm from P. If B is released .then its velocity at a distance of 9 mm from p is:
$$
\left[\text { Take } \frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \mathrm{Nm}^2 \mathrm{C}^{-2}\right]
$$
Two equal charges are placed at a distance of and a third charge is placed at the midpoint. The potential energy of the system is :
If a person brings an electron towards another electron then the change in potential energy of the entire system will be
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Electrostatic Potential energy -
It is the amount of work done by external forces in bringing a body from to a given point against electric force.
or It is defined as negative work done by the electric force in bringing a body from to that point.
- It is Scalar quantity
- SI Unit: Joule
- Dimension: $\left[M L^2 T^{-2}\right]$
Electric Potential energy at a point
If the point charge Q is producing the electric field
Then electric force on test charge q at a distance r from Q is given by $F=\frac{K Q q}{r^2}$
And the amount of work done by the electric force in bringing a test charge from $\infty$ to $r$ is given by
$
W=\int_{\infty}^r \frac{K Q q}{x^2} d x=-\frac{K Q q}{r}
$
And negative of this work done is equal to electric potential energy
$
\text { So }_U=\frac{K Q q}{r}
$
$U \rightarrow$ electric potential energy
$r \rightarrow$ distance between two
Change of potential energy-
if a charge q is moved from $r_1$ to $r_2$ in a electric field produced by charge Q
Then Change of potential energy is given as
$
\Delta U=K Q q\left[\frac{1}{r_2}-\frac{1}{r_1}\right]
$
$\Delta U \rightarrow$ change of energy
$r_1, r_2 \rightarrow$ distances
Potential Energy Of System Of two Charge-
$
U=\frac{K Q_1 Q_2}{r}(S . I)_{\text {where }} K=\frac{1}{4 \pi \epsilon_0}
$
Potential Energy For a system of 3 charges-
$
U=K\left(\frac{Q_1 Q_2}{r_{12}}+\frac{Q_2 Q_3}{r_{23}}+\frac{Q_1 Q_3}{r_{13}}\right)
$
Work energy relation-
$
W=U_f-U_i
$
Where $W=$ work done by an external force
$
\begin{aligned}
& U_f-\text { final P.E } \\
& U_i-\text { initial P.E. }
\end{aligned}
$
The relation between Potential and Potential energy-
$
\begin{aligned}
& U=\frac{K Q q}{r}=q\left[\frac{K Q}{r}\right] \\
& \text { As } \\
& \text { But }=\frac{K Q}{r}
\end{aligned}
$
So $U=q V$
Or potential is defined as Potential energy Per unit charge.
$
\text { i.e } V=\frac{W}{Q}=\frac{U}{Q}
$
Where $V \rightarrow$ Potential
$U \rightarrow$ Potential energy
Electron Volt-
$
1 \mathrm{ev}=1.6 \times 10^{-19} \mathrm{~J}=1.6 \times 10^{-12} \mathrm{erg}
$
It is the smallest practical unit of energy which is used in atomic and nuclear physics.
Electric potential Energy of Uniformly charged sphere-
$
U=\frac{3 Q^2}{20 \pi \epsilon_0 R}
$
Where R - Radius and Q - total charge.
Energy density- It is defined as the energy stored for unit volume.
$
U_v=\frac{U}{V}
$
Where $U-$ Potential Energy and $V-$ Volume.
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