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Electronic Configuration of Elements - Practice Questions & MCQ
Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main
Quick Facts
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48 Questions around this concept.
Solve by difficulty
The electronic configuration for Neodymium is :
[Atomic Number for Neodymium 60]
Choose the correct option having all the elements with $\mathrm{d}^{10}$ electronic configuration from the following :
Match List I with List II :
| List I (Species) | List II (Electronic distribution) | ||
| A. | $\mathrm{Cr}^{+2}$ | I. | $3 \mathrm{~d}^8$ |
| B. | $\mathrm{Mn}^{+}$ | II. | $3 \mathrm{~d}^3 4 \mathrm{~s}^1$ |
| C. | $\mathrm{Ni}^{+2}$ | III. | $3 \mathrm{~d}^4$ |
| D. | $\mathrm{V}+$ | IV. | $3 \mathrm{~d}^5 4 \mathrm{~s}^1$ |
Choose the correct answer from the options given below :
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In the transition elements, the incoming electron occupies (n-1)d sublevel in preference to:
In which of the following pairs, the ions are iso-electronic?
(i) $N a^{+}, \mathrm{Mg}^{2+}$
(ii) $\mathrm{Al}^{3+}, \mathrm{O}^{-}$
(iii) $\mathrm{Na}^{+}, \mathrm{O}^{2-}$
(iv) $\mathrm{N}^{3-}, \mathrm{Cl}^{-}$
the incorrect electron configuration of Nobel gas
No. of electron in 3d subshell and 4s subshell in Cu respectively are
If an extra electron is added to the hypothetical molecule $C_2$, this extra electron will occupy the molecular orbital:
(A) $\Pi_{2 p}$ *
$(B) \Pi_{2 p}$
$(C) \sigma_{2 p^*}$
$(D) \sigma_{2 p}$
The electronic configuration of an element is $1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 3 d^5 4 s^1$ This represents its:
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Electronic configuration of any element
Writing of electronic configuration of any element is based on three rules as told in previous concepts. They are:
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Aufbau principle
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Pauli’s exclusion principle
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Hund’s rule of maximum multiplicity
The distribution of electrons into orbitals of an atom is called its electronic configuration.
The electronic configuration of the different elements can be represented in two ways:
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Subshell notation
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Orbital diagram
Let’s understand with the help of examples:
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The hydrogen atom has only one electron which goes in the orbital with lowest energy, namely 1s.The E.C of hydrogen is 1s1 (subshell notation)
Orbital diagram:
2. The electronic configuration of lithium is 1s2 2s1. Lithium has 3 electrons as atomic number is 3. 2 electrons filled in 1s orbital and 1 electron filled in 2s orbital.
let us consider fluorine (Z = 9) :
F(Z = 9) = 1s2, 2s2, 2px2, 2py2, 2pz1 or
The importance of knowing the exact electronic configuration of an element lies in the fact that the chemical properties of an element are dependent on the behavior and relative arrangement of its electrons.
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