Dielectrics - Practice Questions & MCQ

Dielectric:  A dielectric is an insulating material in which all the electrons are tightly bounded to the nuclei of the atoms and no free electrons are available for the conduction of current. They are non-conducting materials. They do not have free charged particles like conductors have. They are of two types.

1. Polar : The centre of +ve and -ve charges do not coincide. Example $\mathrm{HCl}, \mathrm{H}_2 \mathrm{O}$, They have their own dipole moment
2. Non-Polar: The centers of + ve and -ve charges coincide. Example $\mathrm{CO}_2, \mathrm{C}_6 \mathrm{H}_6$. They do not have their own dipole moment.

electric field Eo . Then net electric field E is given by $E=E_o-E_i$.

This indicates that net electric field is decreased when dielectric is introduced.
The ratio $\frac{E_0}{E}=K$ is called dielectric constant of the dielectric. Hence, Electric field inside a dielectric is $E_i=\frac{E_0}{K}$.

$
E=E_0-E_i \text { and } E=\frac{E_0}{k}
$

So, $E_0-E_i=\frac{E_0}{K}$
or $E_0 K-E_i K=E_0$
or $E_0 K-E_0=E_i K$
or $\quad E_i=\frac{K-1}{K} E_0$
or $\frac{\sigma_i}{\varepsilon_0}=\frac{K-1}{K} \frac{\sigma}{\varepsilon_0}$
or $\sigma_i=\frac{\varepsilon_0-\frac{1}{K}}{K}{ }_\sigma^{\varepsilon_0}$
or $\frac{Q}{A}=\frac{K-1}{K} \frac{Q}{A}$
or $\quad \quad_Q^A=Q_Q^K\left({ }^A-\frac{1}{K}\right)$

This is irrespective of the thickness of the dielectric slab,i.e., whether it fills up the entire space between the charged plates or any part of it.

$C^{\prime}=\frac{\epsilon_0 A}{d-t+\frac{t}{k}}$