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Dielectrics - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Dielectrics is considered one of the most asked concept.

  • 55 Questions around this concept.

Solve by difficulty

When the air in a capacitor is replaced by a medium of dielectric constant K, the capacity,

In the absence of an applied electric field in non-polar materials, that possess non-zero net dipole moment, the electric polarization vector in this

. As shown in the figure, a very thin sheet of aluminium is placed in between the plates of the condenser. Then the capacity

In the absence of an applied electric field in nonpolar dielectric materials, charges are arranged in such a way that

In polar materials, dipole moment of all dipoles in the absence of electric field is

The dielectric constant k  of an insulator cannot be :

Choose the correct statement:

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With the rise in temperature, the dielectric constant $K$ of a liquid

A capacitor has air as a dielectric medium and two conducting plates of area $12 \mathrm{~cm}^2$ and they are $0.6 \mathrm{~cm}$ apart. When a slab of dielectric having area $12 \mathrm{~cm}^2$ and $0.6 \mathrm{~cm}$ thickness is inserted between the plates, one of the conducting plates has to be moved by $0.2 \mathrm{~cm}$ to keep the capacitance same as in the previous case. The dielectric constant of the slab is : $\left(\right.$ Given $\left.\epsilon_0=8.834 \times 10^{-12} \mathrm{~F} / \mathrm{m}\right)$

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Direction :   In the following question, a statement of Assertion ( A ) is followed by a statement of reason (R). Mark the correct choice as 

Assertion : When a dielectric medium is inserted between the plates of an isolated charged capacitor, the charge on the capacitor will remain the same . 

Reason : Charge on a isolated system is conserved .

 

Concepts Covered - 1

Dielectrics

Dielectric:  A dielectric is an insulating material in which all the electrons are tightly bounded to the nuclei of the atoms and no free electrons are available for the conduction of current. They are non-conducting materials. They do not have free charged particles like conductors have. They are of two types.

1. Polar : The centre of +ve and -ve charges do not coincide. Example $\mathrm{HCl}, \mathrm{H}_2 \mathrm{O}$, They have their own dipole moment
2. Non-Polar: The centers of + ve and -ve charges coincide. Example $\mathrm{CO}_2, \mathrm{C}_6 \mathrm{H}_6$. They do not have their own dipole moment.

 

electric field Eo . Then net electric field E is given by $E=E_o-E_i$.

This indicates that net electric field is decreased when dielectric is introduced.
The ratio $\frac{E_0}{E}=K$ is called dielectric constant of the dielectric. Hence, Electric field inside a dielectric is $E_i=\frac{E_0}{K}$.

$
E=E_0-E_i \text { and } E=\frac{E_0}{k}
$


So, $E_0-E_i=\frac{E_0}{K}$
or $E_0 K-E_i K=E_0$
or $E_0 K-E_0=E_i K$
or $\quad E_i=\frac{K-1}{K} E_0$
or $\frac{\sigma_i}{\varepsilon_0}=\frac{K-1}{K} \frac{\sigma}{\varepsilon_0}$
or $\sigma_i=\frac{\varepsilon_0-\frac{1}{K}}{K}{ }_\sigma^{\varepsilon_0}$
or $\frac{Q}{A}=\frac{K-1}{K} \frac{Q}{A}$
or $\quad \quad_Q^A=Q_Q^K\left({ }^A-\frac{1}{K}\right)$

 

This is irrespective of the thickness of the dielectric slab,i.e., whether it fills up the entire space between the charged plates or any part of it.

 

 

$C^{\prime}=\frac{\epsilon_0 A}{d-t+\frac{t}{k}}$

 

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Dielectrics

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