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JEE Main 2020 Question Paper with Solution PDF

To Determine The Coefficient Viscosity Of A Given Viscous Liquid By Measuring The Terminal Velocity Of Given Spherical Body - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

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  • 9 Questions around this concept.

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A cylindrical glass tube with an inner radius of 0.20 mm is dipped into a beaker of mercury. Given the surface tension of mercury is 0.075 N/m and the density is 1000 kg/m3, calculate the height to which the mercury rises in the tube. Assume standard gravity as(g=10 m/s2 ).

 

A spherical metal ball has a diameter (d) of 0.04 meters, and its coefficient of viscosity in a liquid is 0.8 Ns/m². The ball experiences a terminal acceleration (v) of 0.1 m/s² while moving through the liquid. Use this information to measure the coefficient of viscosity in standard units.

An experiment is conducted to determine the coefficient of viscosity (η) of a viscous liquid by measuring the terminal velocity of a spherical body falling through the liquid. The sphere used in the experiment has a radius (r) of 0.03 m and a density (ρ) of 800 kg/m³. The density of the liquid (ρ0) is 1000 kg/m³, and the acceleration due to gravity (g) is 9.81 m/s². The measured terminal velocity of the sphere in the liquid is 0.08 m/s. Calculate the coefficient of viscosity (η) of the given viscous liquid.

An experiment is conducted to determine the coefficient of viscosity (\eta) of a liquid using the measurement of terminal velocity. A spherical body of radius r = 0.02 m and density \rho = 800 kg/m3 is allowed to fall freely in the liquid. The terminal velocity of the sphere is observed to be vt = 0.1 m/s. Given that the acceleration due to gravity is g = 9.81 m/s2, calculate the coefficient of viscosity of the liquid.

An experiment is conducted to determine the coefficient of viscosity (\eta) of a liquid using the measurement of terminal velocity. A spherical body of radius r = 0.03 m and density ρ = 1200 kg/m3 is allowed to fall freely in the liquid. The terminal velocity of the sphere is observed to be vt = 0.08 m/s. Given that the acceleration due to gravity is g = 9.81 m/s2, calculate the coefficient of viscosity of the liquid.

Concepts Covered - 1

To determine the coefficient viscosity of a given viscous liquid by measuring the terminal velocity of given spherical body

Aim
To determine the coefficient of viscosity of a given viscous liquid by measuring the terminal velocity of a given spherical body.

Apparatus
A half metre high,  5 \mathrm{cm} broad glass cylindrical jar with millimetre graduations along its height, transparent viscous liquid, one steel ball, screw gauge, stop clock/watch, thermometer, clamp with stand.

Theory

                                                                               \eta = \frac{2}{9}\left (\rho -\sigma \right )g\frac{r^{2}}{v}

\eta = coefficient of viscosity 

\rho = density of ball

\sigma = density of liquid

r= radius of ball

v= terminal velocity of ball

Knowing r, \rho and \sigma, and measuring v, \eta can be calculated.

Procedure

1.    Take some viscous liquid which must be homogeneous and transparent.

2.    Clean the glass cylinder and fill it with this liquid.

3.    Find the least count of the vertical scale (graduation) of the glass cylinder.

4.    Find the least count and zero error of the stop watch.

5.    Find the least count and zero error of the screw gauge.

6.    Mark the given balls as 1, 2, 3, 4, 5. Giving number 1 to the ball of smallest diameter and number 5 to the ball of maximum diamter.

7.    Find the diameters of the balls as explained in Experiment 2. (Section A)

8.    Make two convenient marks o the cylinder about 40 cm apart, one at a distance of 40 cm from top and other at a distance of 20 cm from bottom.

9.    Drop the ball 1 gently in the liquid. For about 1/3rd of the height of the liquid column, ball falls down with the accelerated velocity. After that this ball falls down with the uniform velocity called terminal velocity. 

10.    When ball covers about 40 cm from the top, start the stop watch.

11.    Stop the stop watch when ball reaches the lower mark which is at 20 cm from the bottom.

12.    Note the distance covered by the ball and time taken to cover this distance.

13.    Repeat the experiment one more time with the steel ball of same diameter.

14.    Repeat the steps 9 to 13 with other four balls also.

 

Calculation - 

\begin{array}{ll}{\text { Mean diameter }} & {D=\frac{D_{1}+D_{2}}{2} \mathrm{mm}} \\ \\ {\text { Mean radius }} & {r=\frac{D}{2} \mathrm{mm}=\ldots \ldots \mathrm{cm}} \\ \\ {\text { Mean time }} & {t=\frac{t_{1}+t_{2}+t_{3}}{3}=\ldots \ldots \mathrm{s}} \\ \\ {\text { Mean terminal velocity, }} & {v=\frac{S}{t}=\ldots . \mathrm{cm} \mathrm{s}^{-1}} \\ \\ {\text { From formula, }} & {\eta=\frac{2 r^{2}(\rho-\sigma) g}{9 v}=\ldots . . \text { C.G.S. units. }}\end{array}

 

Precautions -

1. Liquid should be transparent to watch motion of the ball.
2. Ball should be perfectly spherical.
3. Velocity should be noted only when it becomes constant.

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