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Preparation of Alcohols - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:35 AM | #JEE Main

Quick Facts

  • Grignard Reagent - 1, Reduction by LiAlH4 and NaBH4 is considered one of the most asked concept.

  • 154 Questions around this concept.

Solve by difficulty

 cannot be prepared by :

Alcohols have the general molecular formula:-

If Phenyl magnesium bromide and acetaldehyde are reactants, product formed after hydrolysis would be

The reaction that gives the following molecule as the major product is

Which one of the following is the major product of the given reaction ?

Major product of the following reaction is

Phenyl magnesium bromide reacts with methanol to give

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The aldehydes which will NOT form Grignard product with one equivalent Grignard reagents are :

Through which of the following reactions number of carbon atoms can be increased in the chain?

(i) Grignard reaction

(ii) Cannizaro’s reaction

(iii) Aldol condensation

(iv) HVZ reaction

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Catalytic hydrogenation of acetone-oxine gives :

Concepts Covered - 4

Grignard Reagent - 1

All three types of monohydric alcohols can be prepared by the use of Grignard reagents. Grignard reagents form addition compounds by nucleophile attack with aldehydes and ketones which on hydrolysis with dilute acid yields alcohol.

Mechanism

For example:

Grignard Reagent - 2

Alcohols are produced by the reaction of Grignard reagents with aldehydes and ketones. The first step of the reaction is the nucleophilic addition of Grignard reagent to the carbonyl group to form an adduct. Hydrolysis of the adduct yields alcohol.

Mechanism

Reduction of Anhydrides and Esters

Anhydrides are formed by heating of two (-COOH) groups to remove (H2O) molecule. Aldehydes, ketones, carboxylic acids and derivatives on reduction yield alcohols. A number of reducing agents link Zn/HCl, Na/C2H5OH, LiAlH4 or NaBH4 can be used for this purpose. These derivatives are reduced by nascent hydrogen into corresponding alcohols. 

Some examples include, 

\mathrm{(CH_{3}CO)_{2}O\: +\: 4H\: \xrightarrow[ether]{LiAlH_{4}}\: CH_{3}CH_{2}OH\: +\: CH_{3}COOH}

\mathrm{CH_{3}COOC_{2}H_{5}\: +\: 4H\: \xrightarrow[or\: LiAlH_{4}]{Na/C_{2}H_{5}OH}\: 2CH_{3}CH_{2}OH}

Reduction by LiAlH4 and NaBH4

NaBH4 can only reduce keto groups. But LiAlH4 can reduce even anhydrides and esters. LiAlH4 is a very good reducing agent because (Al) atom present in ir is more covalent than (B) atom in NaBH4. Therefore, Al has more tendency to gain the electrons, thus, it will try to keep the electrons to itself and hence H- will go in a particular manner. Thus, LiAlH4 is better reducing agent than NaBH4.

Mechanism
The mechanism for LiAlH4 occurs in the following steps:

  1. Deprotonation

     
  2. Nucleophilic attack by the hydride ion

     
  3. Nucleophilic attack by the hydride ion

     
  4. Leaving group removal

     
  5. Alkoxide is protonated

Some examples include:

Study it with Videos

Grignard Reagent - 1
Grignard Reagent - 2
Reduction of Anhydrides and Esters

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Books

Reference Books

Grignard Reagent - 1

Chemistry Part II Textbook for Class XII

Page No. : 329

Line : 17

Grignard Reagent - 2

Chemistry Part II Textbook for Class XII

Page No. : 331

Line : 1

E-books & Sample Papers

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